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serious [3.7K]
3 years ago
11

Find the surface area and please explain​

Mathematics
1 answer:
dlinn [17]3 years ago
8 0

Answer:

I NEED MORE DETAILS

Step-by-step explanation:

ITS ALSO BLURRY

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Please Help This Is Math
stira [4]

Answer:

-3

Step-by-step explanation:

5 0
3 years ago
Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.5
masya89 [10]

Answer:

z= \frac{3.44-2.54}{0.45}=2

P(X>3.44) = P(Z>2) = 0.025

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the grade points avergae of a population, and for this case we know the following properties

Where \mu=2.54 and \sigma=0.45

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

So we can find the z score for the value of X=3.44 in order to see how many deviations above or belowe we are from the mean like this:

z= \frac{3.44-2.54}{0.45}=2

So the value of 3.44 is 2 deviations above from the mean, so then we know that the percentage between two deviations from the mean is 95% and on each tail we need to have (100-95)/2 = 2.5% , because the distribution is symmetrical, so based on this we can conclude that:

P(X>3.44) = P(Z>2) = 0.025

5 0
3 years ago
Does anyone know how to substitute -2 into this equation -2x + ( 12 - 9 ) = 2 + 9 + -2x
alexandr1967 [171]

Answer:

-2(-2) + (12-9) = 2 + 9 + -2(-2)

Step-by-step explanation:

6 0
3 years ago
Which expression is equivalent to (4 square root 5 to the power of 3) to the power of 1/2?
diamong [38]

the answer is on the photo

4 0
3 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
Delvig [45]

Answer:

Step-by-step explanation:

a) We would set up the hypothesis test.

For the null hypothesis,

p = 0.25

For the alternative hypothesis,

p ≠ 0.25

b) The test statistic to be used is the z test. The formula is

z = (P - p)/√pq/n

c) Considering the population proportion, probability of success, p = 0.25

q = probability of failure = 1 - p

q = 1 - 0.25 = 0.75

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 141

n = number of samples = 600

P = 141/600 = 0.235

Therefore

z = (0.235 - 0.25)/√(0.25 × 0.75)/600 = - 0.85

d) Recall, population proportion, p = 0.25

The difference between sample proportion and population proportion is 0.25 - 0235. = 0.015

Since the curve is symmetrical and it is a two tailed test, the p for the left tail is 0.25 - 0.015 = 0.235

the p for the right tail is 0.25 + 0.015 = 0.265

These proportions are lower and higher than the null proportion. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score in the left tail 0.198

We would double this area to include the area in the right tail of z = 0.85. Thus

p = 0.198 × 2 = 0.396

e) Since alpha, 0.01 < than the p value, 0.396, then we would fail to reject the null hypothesis.

f) In a sample of 600 cars, we would observe a sample proportion of 0.015 or more away from 0.25 about 39.6% of the time by chance alone. Therefore, the sample result is not statistically significant because it could occur in 39.6% of the time by chance alone.

8 0
3 years ago
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