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solong [7]
3 years ago
14

If you draw a card with a value of 4 or less from a standard deck of cards, I will pay you 165$ if not your pay me $45. (Aces ar

e considered the highest card in the deck.)
enter the expected value of the proposition. Round your answer to two decimals
Mathematics
1 answer:
jekas [21]3 years ago
7 0

Answer: The required expected value is $3.46.

Step-by-step explanation:

Since we have given that

Number of value of 4 or less are

2,3,4

So, there are 12 in numbers.

So, probability would be

\dfrac{12}{52}

Since Aces are considered as the highest card in the deck.

So, remaining probability would be

\dfrac{40}{12}

Amount paid or value of 4 or less = $165

Amount not paid for other case = $45

So, the expected value would be

\dfrac{12}{52}\times 165-\dfrac{40}{52}\times 45\\\\=\dfrac{1980}{52}-\dfrac{1800}{52}\\\\=\dfrac{180}{52}\\\\=3.46

Hence, the required expected value is $3.46.

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what is area of the triangle in a coordinate plane. a 9.0. b 14.0 c16.5. d 24.5 ​
Tresset [83]

Answer:

<h2>c. 16.5</h2>

Step-by-step explanation:

It's the right triangle.

The formula of an area of a right triangle:

A=\dfrac{(leg)(leg)}{2}

Look at the picture.

We have

leg=3,\ leg=11

Substitute:

A=\dfrac{(3)(11)}{2}=\dfrac{33}{2}=16.5

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3 years ago
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Answer:

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Pr (3.88 ≤ X ≤ 5.12)

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A bage contains 5 blue marbles, 3 red marbles, and 2 yellow marbles. You select a marble at radom. What is p(yellow)
vodomira [7]
Total marbles = 5 + 3 + 2 = 10
Total yellow marbles = 2
P(yellow)  = 2/10 = 1/5

Answer: 1/5
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3 years ago
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Yuliya22 [10]

Answer:

Step-by-step explanation:

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6 0
3 years ago
A fisherman uses a spring scale to weigh a tilapia fish. He records the fish weight as a kilograms and notices that the spring s
belka [17]

Answer:

k = \frac{980a}{b}

Step-by-step explanation:

Fisherman noticed a stretch in the spring = 'b' centimetres

Weight of the fish = a kilograms

If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,

F = kΔx

Where k = spring constant

Δx = stretch in the spring

F = weight applied

F = mg

Here 'm' = mass of the fish

g = gravitational constant

F = a(9.8)

  = 9.8a

Δx = b centimetres = 0.01b meters

Therefore, 9.8a = k(0.01b)

k = \frac{9.8a}{0.01b}

k = \frac{980a}{b}

Therefore, spring constant of the spring will be determined by the expression, k = \frac{980a}{b}

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