This is hard to write... I hope this makes sense to you...
3x-2y=-39
x+3y= 31
We want to use elimination therefor, we need to either get our x or our y to add together to get zero.
To do this, we will multiply -3 to (x=3y=31)
NEW EQUATION
3x-2y=-39 PLUS
-3x-9y= -93 Equals
Answer: -11y= -54
y= 4.9
Plug in to solve for x (put new y in)
3x-2(4.9)=-39
x= -9.73
Im not sure if it’s right but I think it’s -6,17
So its a fraction all you would do is divide 96 by 64 and you would 1 and one half
Answer:
which is the same as writing 56y^2m
====================================================
Explanation:
Let's focus on the coefficients 8 and 7 for now.
To find the LCM of those values, list out the multiples. Circle the smallest number that can be found in both sets at the same time.
- multiples of 8 are: 8, 16, 24, 32, 40, 48, 56, 64, ...
- multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56, 63, ....
We see that 56 is the LCM of 7 and 8.
Or you could use this shortcut
LCM = (x*y)/GCF
where x and y are the two numbers. The mention of "GCF" refers to the GCF of x and y. In this case, the GCF is 1 so,
LCM = (x*y)/GCF = (8*7)/1 = 8*7 = 56.
----------------------
Once we determine that, we look at the variable terms now.
The y^2 and m will be tacked onto the 56 to arrive at the final answer 56y^2m
This is because y and m are the unique variables, and we go for the highest exponent of each. It's similar to the LCM formula used earlier.