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3 years ago

If 48% of the students in a certain college are female and there are 2,400 female students, how many students are male?

Mathematics

1 answer:

brilliants [131]3 years ago

6 0

Answer:

2,600 male students

Step-by-step explanation:

$\frac{2,400}{0.48} = 5,000$

There are 5,000 students in total.

Since 2,400 of them are female, the remaining students must be male.

5,000 - 2,400 = 2,600 male students

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ABCD is a quadrilateral. Three of the angles of ABCD measure 100°, 87, and 106°, respectively. Find the measure of the

ladessa [460]

Answer:

Step-by-step explanation:

The angles in a quadrilateral add up to 360 degrees.

100 + 87 + 106= 293

360 - 293 = 67

8 0

3 years ago

Read 2 more answers

I need help please and thank you and show work

ioda

Answer:

Ivy is correct

Step-by-step explanation:

the perimeter of a parallelogram can be written as P= 2(a+b), where a and b are the lengths of the sides of the parallelogram.
since the parallelogram has been dilated by a scale factor of 0.6, we multiple the original side lengths by 0.6.
12 × 0.6 = 7.2
16 × 0.6 = 9.6
Plug into the equation
P=2(7.2+9.6)
P=2(16.8)

P= 33.6

You can also solve by plugging in the original values and multiplying the answer by 0.6.
P=2(12+16)(0.6)
P=2(28)(0.6)
P=(56)(0.6)

P=33.6

5 0

2 years ago

Thanks for the answer

iragen [17]

Answer:

12 books

Step-by-step explanation:

30 multiply by 2/5=12 books that were sold to co-workers.

3/5 which is the remainder multiplied by 1/2 =3/10

3/10 multiply by 30 =6 books sold to her neighbours

now that 30 is the original subtract12 +6

4 0

2 years ago

WILL NAME BRAINLIEST!!<br>I forgot how to do this over quarantine I guess . . . ;-;

Ymorist [56]

Answer:

x = 37

Step-by-step explanation:

Power Theorem: 10 x (10 + 26) = 8 x (8 + x)

360 = 8 x (8 + x)

8 + x = 45

x = 37

8 0

3 years ago

Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. N an 1 4 2 −12 3 36 t

Rzqust [24]

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is $\sum_{n=4}^{15} 5(-2)^{n-1}$$$

<h3>What is sequence ?</h3>

Sequence is collection of numbers with some pattern .

Given sequence

$a_{1}=5\\\\a_{2}=-10\\\\\\a_{3}=20$

We can see that

$\frac{a_1}{a_2}=\frac{-10}{5}=-2\\$

and

$\frac{a_2}{a_3}=\frac{20}{-10}=-2\\$

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2

Now $n^{th}$ term of this Geometric progression can be written as

$T_{n}= 5\times(-2)^{n-1}$

So summation of 15 terms can be written as

$\sum_{n=4}^{15} T_{n}\\\\$\\$\sum_{n=4}^{15} 5(-2)^{n-1}$$$

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is $\sum_{n=4}^{15} 5(-2)^{n-1}$$$

To learn more about Geometric progression visit : brainly.com/question/14320920

8 0

3 years ago