Answer:
The correct answer is;
No, the quadrilateral is not always a parallelogram
Step-by-step explanation:
Since there are only four opposite angles in a quadrilateral there are only two possible angle bisectors of the opposite angles also, the angle bisectors of a pair of opposite angles of a quadrilateral will intersect within the quadrilateral and therefore they cannot form the sides of a parallelogram
Therefore, the answer is no, the quadrilateral is not always a parallelogram.
The answer is 6 hope this helps
He received 102.18 dollars
The coordinates for D are (-4, -7)
First we must locate point B as it is vital to finding the midpoint of BD. To do this, we take the average of the endpoints AC since B is its midpoint.
x values = -9 + 1 = -8
Then divide by 2 for the average -8/2 = -4
y values = -4 + 6 = 2
Then divide by 2 for the average 2/2 = 1
Therefore B must be (-4, 1)
Now we know the values of E must be the average of B and D. So we can write equations for each coordinate since we know they are averages.
x - values = (Bx + Dx)/2 = Ex
(-4 + Dx)/2 = -4 ---> multiply both sides by 2
-4 + Dx = -8 ---> add -4 to both sides
Dx = -4
y - values = (By + Dy)/2 = Ey
(1 + Dy)/2 = -3 ---> multiply both sides by 2
1 + Dy = -6 ---> subtract 1 from both side
Dy = -7
So the coordinates for D must be (-4, -7)
Answer:
50.272 in^2
Step-by-step explanation:
Step one:
Given data
Circles are described using the diameter parameter
Diameter of the circle is 8 inches
radius = 4 inche= d/2
Step two:
The area of the circle is
A= πr^2
A= 3.142*4^2
A=3.142*16
A=50.272 in^2
