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GrogVix [38]
3 years ago
15

To make a certain shade of orange calvin uses a rate of 2 ounces of yellow paint to 5 ounces of red paint if he uses 200 ounces

of red paint how many ounces of yellow paint
Mathematics
1 answer:
ycow [4]3 years ago
4 0
Answer: 80 ounces of yellow paint

Working:
As we know 2 ounces of yellow paint to 5 ounces of red paint, we can make a ratio:

2:5

Then we look at the question which says 200 ounces of red paint, so we replace the 5 ounces of red paint in the ratio with 200.

2:200

Then we figure out how much the 5 has been multiplied by to get to 200. We do this by doing

200 divide 5 = 40

Therefore we times the 2 ounces of yellow paint by 40 which gets us:

80:200

We can think of it as a fraction too to confirm our answer:

Simplify 80 / 200

We get 2 / 5.

If you need me to further explain something please just ask :)
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a bag contains 6 red 4 blue and 8 green marbles how many of each color should be added so that the total number of marbles is 27
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Answer:

17.00

Step-by-step explanation:

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Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0
Rus_ich [418]

The Solution:

Given the equation of a line:

6x-y-4=0

We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

\begin{gathered} \text{  Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\  \\ Slope=m_1=6 \end{gathered}

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

\begin{gathered} m_2=\frac{-1}{m_1}=\frac{-1}{6} \\  \end{gathered}

Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

y-y_1=m_2(x-x_1)

In this case,

\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}

Substituting these values in the formula, we get the required equation is:

\begin{gathered} y--1=\frac{-1}{6}(x--12) \\  \\ y+1=-\frac{1}{6}(x+12) \end{gathered}

Cross multiplying, we get

\begin{gathered} 6y+6=-x-12 \\  \\ 6y+x+6+12=0 \\  \\ 6y+x+18=0 \end{gathered}

Therefore, the correct answer is:

6y+x+18=0

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1 year ago
ABCD is a square. What is the measure of angle BAC? °
gladu [14]
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