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3 years ago

13

Baseball hat for $22.90 at 5% sales tax

1 answer:

exis [7]3 years ago

3 0

Answer:I got $21.76

Step-by-step explanation:

;-;

You might be interested in

Pre-Calculus - Systems of Equations with 3 Variables please show work/steps

inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0

3 years ago

Helppppppp pleaseeee

Mariana [72]

$\boxed{a_1=-4}\\\\a_2=a_1\cdot\,?\\\\-24=-4\cdot\,?\\\\\boxed{?=6}$

Answer B.

6 0

3 years ago

What are the solution

AleksandrR [38]

Answer:

B

Step-by-step explanation:

We can get two equations from the inequality:

$3x+2>9\\3x+2>-9$

We just need to simplify both equations to get our answers:

$3x+2>9\\3x>7\\x>\frac{7}{3}$

$3x+2>-9\\3x>-11\\x>\frac{-11}{3}$

The two answers we get are:

$x\frac{7}{3}$

Which is also B.

3 0

2 years ago

Write the repeating decimal as a fraction.<br>0.1872

Gekata [30.6K]

117/625 is the fraction

7 0

3 years ago

Read 2 more answers

Jacob needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.

dalvyx [7]

An inequality that represent the number of cans, c, that Jacob must still collect is $c\geq 56$ .

<u>Step-by-step explanation:</u>

Here we have , Jacob needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items. We need to solve the following :

<u>Part A: </u>

Write and solve an inequality to represent the number of cans, c, that Jacob must still collect.

Jacob has collected 64 cans . Jacob need to collect at least 120 cans for a food drive to earn community service credit , Let Number of cans that Jacob have to collect is c , So following is the inequality for above scenario:

⇒ $c+64\geq 120$

⇒ $(c+64)-64\geq 120-64$

⇒ $c\geq 56$

Therefore , An inequality that represent the number of cans, c, that Jacob must still collect is $c\geq 56$ .

8 0

4 years ago