The key with these problems is to find which function has the closest y-intercept to the graph, and then try to figure out which one best approximates the slope.
Here are our options:
<span>A. y = x + 4
B. y = 4x + 9
C. y = x + 18
D. y = 3x + 22
Which has the closest approximation of the y-intercept?
The y-intercept is not directly given, but we can assume it is less than 10.
That leaves us with A and B.
Which has the closest approximation of the slope?
The graph, on average, seems to move up about 60 and over about 15.
Slope = rise/run = 60/15 = 4. Although the slope isn't exactly 4, it's much closer to 4 than 1, which is slope for option A.
Therefore, the answer is
B) y= 4x + 9
</span>
Answer:
f(x) = 0.43 * 
* 
*(x + 10)
Step-by-step explanation:
We have a 6th degree polynomial f(x)
r = 3 is a root of f with multiplicity 2
r = 1 is a root of f with multiplicity 3
f(-5) = -29721.6
f(-10) = 0
Then: f(x) = a*((x -3)^2 ) * ((x - 1)^3)*(x + 10)
f(-5) = a * (-8)^2 * (-6)^3 * (5) = -29,721.6
a* (64) * (-216)* 5 = -29,721.6
-a*69,120 = -29,721.6
a = -29,721.6/-69,120
a = 0.43
so
f(x) = 0.43 * * *(x + 10)
Answer:
what do you need?
Step-by-step explanation:
I don't see a question.
Answer:
Step-by-step explanation:
Let the weight of the bag of sand with an unknown weight be given as "x" pounds. Then, the difference between the weight of an average bag of sand which is given to be as 22.3 pounds, is given as 
. Therefore, the absolute value function describing the difference between the weight of an average bag of sand and a bag of sand with an unknown weight will be given as: 
.
Let us represent this by f(x) or y. And thus, we get:
Answer:
200.96 feet
Step-by-step explanation:
We have a pool with a radius of 28 feet.
They also tell us that there is a path around the pool and its width is 4 feet.
Thus:
The radius of the outer edge of the pool path would be equal to the radius of the pool plus the width of the path.
= (28 + 4) feet
= 32 feet
To find the length of the fence, we need to find the circumference of the outside of the pool path. The radius is then equal to 32 feet.
The circumference of the outer edge of the pool path would be equal to the perimeter.
p = 2 * pi * r
replacing
p = 2 * 3.14 * 32
p = 200.96 feet
therefore 200.96 feet are needed
