Triangle PQR has vertices (2,2) (5,-4) and (-4,-1). What type of triangle is triangle PQR

The function f(x)=−2(0.25)x+1 is shown. Select from the drop-down menus to correctly describe the end behavior of f(x).

Viktor [21]

Answer:

Q1

cos 59° = x/16

x = 16 cos 59°

x = 8.24

Q2

BC is given 23 mi

Maybe AB is needed

AB = √34² + 23² = 41 (rounded)

Q3

BC² = AB² - AC²

BC = √(37² - 12²) = 35

Q4

Let the angle is x

cos x = 19/20

x = arccos (19/20)

x = 18.2° (rounded)

Q5

See attached

Added point D and segments AD and DC to help with calculation

BC² = BD² + DC² = (AB + AD)² + DC²

Find the length of added red segments

AD = AC cos 65° = 14 cos 65° = 5.9

DC = AC sin 65° = 14 sin 65° = 12.7

Now we can find the value of BC

BC² = (19 + 5.9)² + 12.7²

BC = √781.3

BC = 28.0 yd

All calculations are rounded

6 0

3 years ago

I need help with my homework its about adding whole numbers

Vinvika [58]

Answer:

1- 60

2-80

3-336a

4-1584x

5-1673b

6-61

7-180

8-216x

9-420

10-1402b

11-784a

12-1818

13-4547y

14-5224

15-6382z

8 0

3 years ago

Suppose that w and t vary inversely and that t = 5/12

Svetlanka [38]

Answer:

Option B. t=5/3w ;1/3

Step-by-step explanation:

We are told that $w$ varies Inversely with $t$ thus generally speaking $w$ ∝ $\frac{1}{t}$ since they are inverted, <u>otherwise</u> if they were proportionally varied then $w$ ∝ $t$ . This means that there is a constant value ( $a$ ) for which $w$ is inversely proportional to $t$ and can be mathematically expressed as:

$w=\frac{a}{t}$ Eqn. (1)

Now since we are given the values of $w=4$ and $t=\frac{5}{12}$ , we can plug them in Eqn. (1) and find our constant of proportionality $a$ as follow: