The equation of perpendicular bisector of BC is
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Further explanation:
A perpendicular bisector passes through the mid-point of a line so to get an ordered pair from which the perpendicular bisector will pass we need to find the mid-point of BC.
So the perpendicular bisector will pass through (-1,3)
Let m1 be the slope of BC
Then
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Let m2 be the slope of perpendicular bisector
We know that the product of slopes of perpendicular lines is -1.

The standard form of point-slope form of line is:
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Putting the value of slope of bisector we get
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To find the value of b, put the ordered pair (-1,3) in the equation

Putting the values of m and b in standard form
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Hence the equation of perpendicular bisector of BC is
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Keywords: Perpendicular bisector, Point-slope form
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