The total number of digits used when the first 2002 positive even integers are written is 4 digits
<h3>How to find the number of sequence?</h3>
Using arithmetic sequence,
nth term = a + (n - 1)d
where
- a = first term
- d = common difference
- n = number of terms
a = 2
d = 2
nth term = 2 + (2002 - 1)2
nth term = 2 + 4002
nth term = 4004
learn more on sequence here: brainly.com/question/15456604
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Answer:
y = -
x + 7
Step-by-step explanation:
Ambos puntos (3, 5) y (6, 3) están en esta línea.
The Answer Would Be 16
How I Found The Answer:
2 x 2 x 2 x 2 = 16
Answer:
<em>T</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>y</em><em>.</em>
Step-by-step explanation:
<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>w</em><em>o</em><em>r</em><em>k</em><em>s</em><em> </em><em>o</em><em>u</em><em>t</em><em> </em><em>!</em><em>!</em>
Answer:
<em>1680 is the answer.</em>
Step-by-step explanation:
Here, we have 11 letters in the word <em>MISSISSIPPI.</em>
Repetition of letters:
M - 1 time
I - 4 times
S - 4 times
P - 2 times
As per question statement, we need a substring MISS in the resultant strings.
So, we need to treat MISS as one unit so that <em>MISS always comes together in all the strings</em>.
The resultant strings will look like:
<em>xxxxMISSxxx</em>
<em>xxMISSxxxxx</em>
<em>and so on.</em>
After we treat <em>MISS </em>as one unit, total letters = 8
Repetition of letters:
MISS - 1 time
I - 3 times
S - 2 times
P - 2 times
The formula for combination of letters with total of <em>n </em>letters:

where <em>p, q</em> and <em>r</em> are the number of times other letters are getting repeated.
<em>p = 3</em>
<em>q = 2</em>
<em>r = 2</em>
<em></em>
So, required number of strings that contain MISS as substring:

So, <em>1680 is the answer.</em>