Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Answer:
y=-3/5x+16
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(13-19)/(5-(-5))
m=-6/(5+5)
m=-6/10
simplify
m=-3/5
y-y1=m(x-x1)
y-19=-3/5(x-(-5))
y-19=-3/5(x+5)
y=-3/5x-15/5+19
y=-3/5x-3+19
y=-3/5x+16
Answer:
D.
Step-by-step explanation:
In order to eliminate, the numbers must eliminate. If the second equation is multiplied by 3, then the 3 and the -3 can be eliminated. Since it is multiple choice, we can plug in x = 12 and y = 10 to see if they are correct. 12 + 30 = 42 and 24 - 10 = 14, so D is correct.
Answer:
98.5 cm2
Step-by-step explanation:
