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3 years ago

¿Cómo se mide el grado de una ecuación algebraica?

1 answer:

3 0

Answer: El grado de una ecuación lo marca el monomio (o término) de mayor grado absoluto. 5x + 3 = 2x + 1 Ecuación de primer grado (cada término posee solo una incógnita y su exponente es uno) . 5x + 3 = 2x 2 + x Ecuación de segundo grado.

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Solve for x: the quantity of x plus 4 over 3 = 2.

defon

Answer:

x =2

Step-by-step explanation:

(x+4) /3 = 2

Multiply each side by 3

(x+4) /3 *3= 2*3

x+4 = 6

Subtract 4

x+4-4 = 6-4

x =2

8 0

2 years ago

Read 2 more answers

bath walked 10 7/8 miles one week she walk 2 1/4 fewer miles the following week about how many miles did she walk the second wee

bagirrra123 [75]

Answer:

8 and 5/8

Step-by-step explanation:

The question is just subtraction of fractions. First, you subtract the whole numbers. 10-2=8. Then you subtract the fractions. To do this, you have to make them equivalent. Just multiply the 1/4 by 2 and you get 2/8. Now, 7/8 - 2/8 = 5/8. Your final answer is 8 and 5/8

7 0

2 years ago

Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ

Allisa [31]

Answer:

Probability of stopping the machine when $X < 9$ is 0.0002

Probability of stopping the machine when $X < 10$ is 0.0013

Probability of stopping the machine when $X < 11$ is 0.0082

Probability of stopping the machine when $X < 12$ is 0.0399

Step-by-step explanation:

There is a random binomial variable $X$ that represents the number of units come off the line within product specifications in a review of $n$ Bernoulli-type trials with probability of success $0.91$ . Therefore, the model is ${15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}$ . So:

$P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002$

$P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013$

$P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082$

$P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399$

Probability of stopping the machine when $X < 9$ is 0.0002

Probability of stopping the machine when $X < 10$ is 0.0013

Probability of stopping the machine when $X < 11$ is 0.0082

Probability of stopping the machine when $X < 12$ is 0.0399

8 0

2 years ago

A sample of 140 Vopstra customers have had their annual phone charge recorded for the previous calendar year. The data were used

taurus [48]

Answer:

Correct option: (a)

Step-by-step explanation:

A confidence interval is an interval estimate of the parameter value.

A (1 - α)% confidence interval implies that the confidence interval has a (1 - α)% probability of consisting the true parameter value.

If 100 such confidence intervals are made then (1 - α) of these intervals would consist the true parameter value.

The 92% confidence interval for the mean annual phone charge of all Vopstra customers is:

$\$470\pm \$65=(\$405, \$535)$

This confidence interval implies that true mean annual phone charge of all Vopstra customers is contained in the interval ($405, $535) with 0.92 probability.

Thus, the correct option is (a).

6 0

3 years ago

PLZ HELP, DUE TONIGHT!! Find the values of a and b such that f(x) is continuous at x=1

Sedaia [141]

Answer:

a = 2, b = -4

Step-by-step explanation:

To make the given piecewise function continuous we need:

ax² - b = 6 and 5ax + b = 6 at x = 1

It gives us the system:

a(1²) - b = 6 ⇒ a - b = 6
5a(1) + b = 6 ⇒ 5a + b = 6

Sum of the two:

a - b + 5a + b = 6 + 6
6a = 12
a = 2

Then b is:

2 - b = 6
b = -4

6 0

2 years ago