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Anuta_ua [19.1K]
3 years ago
9

Whoever is really good at math I need UUU!!!

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0
Subtract 3x from both sides: −2y = −3x + 16; divide both sides by −2: y x = − 3 2 8.

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The Kaibab Trail at the Grand Canyon begins at 7,000 feet above sea level. If you descend on the trail 4,500 feet to the Colorad
lutik1710 [3]

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3875 feet above sea level

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3 years ago
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What is the area of the shaded region? (Use 3.14 for Pi) *
love history [14]

Answer:

The area of the shaded region is the difference between the areas of the rectangle and the square.

Step-by-step explanation:

8 0
3 years ago
X= <br> 5<br> 10<br> 6<br> Please help
Lerok [7]

Answer:

x = 6

Step-by-step explanation:

(segment piece) x (segment piece) =   (segment piece) x (segment piece)

2*x = 3*4

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8 0
3 years ago
On a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24
Helen [10]

Answer:

30.06 degree Celsius at 4:00 PM.

Step-by-step explanation:

We have been given that on a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24 degrees C. At noon the air conditioner is turned​ off, and the people go home. The temperature outside is a constant 35 degrees C for the rest of the afternoon. The time constant for the building is 5 ​hr. We are asked to find the temperature inside the building at 4:00 PM.

We will use Newton's law of cooling to solve our given problem.

T(t)=M_0+(T_0-M_0)e^{-kt}, where

T(t) = Temperature after t hours.

M_0 = Temperature of surrounding environment,

k = Time constant.

\frac{1}{k}=5\Rightarrow k=\frac{1}{5}

Upon substituting our given values in Newton's cooling law, we will get:

T(t)=35+(24-35)e^{-\frac{t}{5}}

T(t)=35-11e^{-\frac{t}{5}}

To find the temperature at 4:00 pm, we will substitute t=4 in our formula as:

T(4)=35-11e^{-\frac{4}{5}}

T(4)=35-\frac{11}{e^{\frac{4}{5}}}

T(4)=35-\frac{11}{2.2255409284924674}

T(4)=35-4.9426186052894379601

T(4)=30.05738139471

T(4)\approx 30.06

Therefore, the temperature inside building would be approximately 30.06 degree Celsius at 4:00 PM.

5 0
3 years ago
Can someone please answer. There is one problem. There's a picture. Thank you!
Over [174]
I believe the answer is A, 6,720.
4 0
3 years ago
Read 2 more answers
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