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2 years ago

How to solve -3z+1=7

Mathematics

2 answers:

Alenkasestr [34]2 years ago

6 0

Answer: z = -2

Step-by-step explanation:

The goal is to get the variable "z" alone, so we have to simplify it. You subtract 1 from each side, making the left side read "-3z" and the right simply have 6. You then have to get rid of the coefficient, which is the number that your variable (z) is being multiplied by. So you then divide each side by -3. You will be left with "z = -2" because 6 divided by -3 is equal to -2.

Svetllana [295]2 years ago

4 0

Answer:

Step-by-step explanation:

Subtract 1 from 7, and then divide 6 by 3.

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What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

skad [1K]

Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^2+7x+4=0$

$a=2\\b=7\\c=4$

substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

$x=\frac{-7\pm\sqrt{17}} {4}$

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

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2 years ago

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Dafna11 [192]

Answer:

Step-by-step explanation:

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6 months ago

this weekend you're going to go kayaking down the Colorado River. the rental shop charges $13.00 to rent a kayak with paddles pl

SCORPION-xisa [38]

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3 years ago

Read 2 more answers

Of is directly proportional toy and x = 45 when

kompoz [17]

Answer:

if x=ky, where k is constant.

value of x

45/3=k3/3

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3 years ago

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gavmur [86]

First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}$

solve for "x"

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