All categories

2 years ago

I'm just confused on how I go about doing this.

Mathematics

1 answer:

Nady [450]2 years ago

7 0

Answer:

<h3>私があなたの質問を理解していないこと</h3><h3>私が今あなたの質問を理解していないこと</h3>

You might be interested in

7/5 + 4/20<br><br> Answers should be in format example: 5/2 or 2/5. No decimals or mixed numbers.

kipiarov [429]

Answer: 32/20 or 8/5

Step-by-step explanation: Turn 7/5 into 28/20. Do 28/20 plus 4/20. That equals 32/20 or 8/5.

7 0

3 years ago

Read 2 more answers

I need help I'm stuck ?

likoan [24]

$v = \frac{4}{3} \times \pi \times ({ \frac{8}{2} })^{3} \\$

$v = \frac{4}{3} \times 3 \times {4}^{3} \\$

$v = {4}^{4}$

$v = {2}^{8}$

$v = 256 \: \: {cm}^{3}$

7 0

2 years ago

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

7 0

3 years ago

15x^2 - 25 answer with a complete sentence

zubka84 [21]

Answer:

No, the following expression is not a difference of squares. Binomial can not be factored as the difference of two perfect squares. 3 is not a square.

Step-by-step explanation:

Factor

15x^2 - 25

(15x)^2(-5)^5

Divide by 3 and factor

5(3x^2-5)

"Theory:

A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression."

I put a picture to help u understand.

7 0

3 years ago

HELP 7TH GRADE I WILL GIVE BRAINLIEST

Feliz [49]

Answer:

Step-by-step explanation:

theres a 90 degree angle and a has a 95 so thats pretty close

5 0

2 years ago