4. line them up least to greatest and the one in the middle is the median, which is 4.
ANSWER
3) b
EXPLANATION
Given that:

and

Recall that the sine and cosine functions are equal for complementary angles.
This implies that,


Answer:
0.00597
Step-by-step explanation:
Given,
Total number of cards = 52,
In which flush cards = 20,
Also, the number of spade flush cards = 5,
Since,

Thus, the probability of a hand containing a spade flush, if each player has 5 cards




= 0.00597