Based on the knowledge of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions, the value of the <em>sine</em> function is equal to - √731 / 30.
<h3>How to find the value of a trigonometric function</h3>
Herein we must make use of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions to find the right value. According to trigonometry, both cosine and sine are <em>negative</em> in the <em>third</em> quadrant. Thus, by using the <em>fundamental trigonometric</em> expression (sin² α + cos² α = 1) and substituting all known terms we find that:
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sin θ ≈ - √731 / 30
Based on the knowledge of <em>trigonometric</em> expressions and properties of <em>trigonometric</em> functions, the value of the <em>sine</em> function is equal to - √731 / 30.
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Answer:
Step-by-step explanation:
For Question 3, we are simply taking an input for the function, as a value of x and solving the equation. For part a, we substitute 3/14 into the first function, and solve it:
f(x) = 7(3/14) + 2
f(x) = 21/14 + 2
f(x) = 49/14
f(x) = 7/2
For part b, we take the input of -3 into the second function and solve the equation:
h(x) = 4(-3)^2
h(x) = 4(9)
h(x) = 36
For Question 4, we are simply solving this equation by isolating the x variable. First, we simplify the equation to 4-5x+15+2x = -2 and simplify this again to -3x+19 = -2. Now, we can subtract 19 from both sides of the equation to get -3x = -21. Lastly, we isolate the x variable by dividing both sides of this equation by -3, to get x = 7.
Answer:
16%
Step-by-step explanation:
The additional wage amount is $80.
The original wage amount is $500.
The ratio of the two is ...
$80/$500 = 0.16 = 16/100
To express that ratio as a percentage, multiply it by 100%.
0.16 × 100% = 16%
_____
It might help you to think of the percent sign (%) as a fancy way to write "per hundred" (/100). Of course, using your knowledge of place value, you know that 0.16 = sixteen hundredths = 16/100.
Realizing the meaning of the % sign, you can immediately write this as 16%.
Quadrant 2 is the only one that can satisfy the condition. In there, x<0 and y>0