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SCORPION-xisa [38]
3 years ago
12

When multiplying a binomial by a trinomial, is the degree of the product always 5? Explain.

Mathematics
2 answers:
Naya [18.7K]3 years ago
4 0

Given that a binomial is multiplied by a trinomial.

A binomial means containing two terms normally

x+a

Trinomial is containing 3 terms may be

ax^2+bx+c

When we multiply we can get degree 3 also as shown above.

Hence the statement is false.

When a binomial is multiplied by a trinomial getting a product of degree 5 is only occasional and not always.

DedPeter [7]3 years ago
4 0

Answer:

...

Step-by-step-by-step explanation:

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Answer:

B, D, and E.

Step-by-step explanation:

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B) A solution to the system is (-1, -2). This is true because this is the only point where the lines intersect.

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E) One of the equations is 3x+y=-5. If you put this into slope-intercept form, you will find out that the equation is y=-3x-5. This is true because the y-intercept of this is -5 and the slope of this is -3.

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Kala bought two types of cheese at a deli. She bought 0.50 pound of American cheese and 1.25 pounds of Swiss cheese. The bar dia
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In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older
Viktor [21]

Answer:

p_v =P(t_{(63)}>2.5)=0.0075  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=45 represent the mean height for the sample  

s=16 represent the sample standard deviation for the sample  

n=64 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=64-1=63  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(63)}>2.5)=0.0075  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

6 0
3 years ago
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