We are given:
p = probability = 0.12<span>
n = total students = 39 </span>
x = left handers = 5<span>
u = mean = p* n = 4.68
σ = standard dev = √ ( n*p*(1-p)) = √ ( 39 * 0.12 * 0.88 ) =
2.03</span>
Calculating for the z score:
z = (x – u) / σ<span>
z = (5 – 4.68) / 2.03</span>
<span>z
= 0.1576 = 0.16
</span>
Using the standard tables for z, the p value is:
p value = 0.5636 = 56.36%
Hence there is a 56.36% chance.
<span> </span>
Answer: the answer is D. the spread is from 1 to 6.
Step-by-step explanation:
Choice C is the correct answer because

So in short, 
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The mistake Jerry likely made was that he only cubed the 2 and didn't realize the 6 was part of that cubing process. It seems he didn't add first and decided to cube before adding.
This is probably what steps Jerry did

But as mentioned, those steps are incorrect because the 6 is part of the cubing operation. In other words, Jerry should have added the 6+2 first before cubing afterward (due to PEMDAS determining the order of operations).
Or you could think of it like this

Answer:
Perimeter of △BDC=Sum of all the sides=BD+DC+CB=15+15+15=45
Step-by-step explanation:
Given ΔABC is an isosceles triangle, thus, AB=BC=x and AC=12,
perimeter of △ABC is=42
⇒x+x+12=42
⇒2x=30
⇒x=15
Thus, AB=BC=15
Now, △BDC is an equilateral triangle therefore BD=DC=BC=x
Since, x=15, therefore BD=DC=BC=15
Now, Perimeter of △BDC=Sum of all the sides=BD+DC+CB=15+15+15=45
Answer:
(x, y) = (1/2, -1)
Step-by-step explanation:
Subtracting twice the first equation from the second gives ...
(2/x +1/y) -2(1/x -5/y) = (3) -2(7)
11/y = -11 . . . . simplify
y = -1 . . . . . . . multiply by y/-11
Using the second equation, we can find x:
2/x +1/-1 = 3
2/x = 4 . . . . . . . add 1
x = 1/2 . . . . . . . multiply by x/4
The solution is (x, y) = (1/2, -1).
_____
<em>Additional comment</em>
If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.
A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).