20 - 12 = x
combine like terms, theres ur answer
Answer:
Two times at (-1,0) and (2.5,0)
Step-by-step explanation:
When the graph intersects or touches x-axis, y is equal to 0
so y = -2x^2 + 3x + 5
=> 0 = -2x^2 + 3x + 5
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
so a = -2
b = 3
c = 5
substitute in the formula
x = [-3 +/- √(3^2 - 4x-2x5)]/2(-2)
x = [-3 +/- √(9 + 40)]/(-4)
x = [-3 +/- 7]/(-4)
x1 = (-3 + 7)/(-4) = 4/-4 = -1
x2 = (-3 - 7)/(-4) = -10/-4 = 5/2 = 2.5
so the graph has two x-intercepts (-1,0) and (2.5,0), therefore it intersects x-axis two times
n, n + 2, n + 4 - three consecutive even integers
3n = 2(n + 4) + 4 |use distributive property
3n = (2)(n) + (2)(4) + 4
3n = 2n + 8 + 4
3n = 2n + 12 |subtract 2n from both sides
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
Answer: 12, 14, 16.
Step-by-step explanation:
Angle 1 2 and 3 are angles that are in a triangle and all the angles in a triangle always add up to 180
so <1 +<2 +<3=180
Hope that helps :)
