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quester [9]
2 years ago
13

What is the relationship between slope and unit rate?​

Mathematics
1 answer:
Alja [10]2 years ago
8 0

Answer:

For an equation such as y = 2.6x, the slope is the unit rate, which is the coefficient of x. For a table, <u>the change in y divided by the change in x</u> is the unit rate, or slope.

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What is the difference between 23 and 0.33​
pshichka [43]

Answer:

22.67

Step-by-step explanation:

take 0.33 away from 23 to find the answer

4 0
3 years ago
Read 2 more answers
Does this set of ordered pairs represent a function? Why or why not. Don’t need a step to step just the answer
Scrat [10]

Answer:

D. Yes,because every x-value corresponds to exactly one y-value.

Step-by-step explanation:

The given ordered pairs are;

{(-5,-5),(-1,-2),(0,-2),(3,7),(8,9)}

We do not have the same x-value corresponding to more than one y-value.

We can see from the ordered pairs that every x-value corresponds to exactly one y-value.

Therefore the graph of this relation will pass the vertical line test.

3 0
3 years ago
Read 2 more answers
1, what is p(yellow, green) if there are 4 blue, 3 green, 2 yellow marbles
Mariulka [41]
1. \frac{2}{3}

2. \frac{4}{4} or 1

3. \frac{3}{9}

4. \frac{0}{0}
6 0
3 years ago
Simply 2 x b x b x b x 4
elena-s [515]
2×4=8
b×b×b= b^3
so putting them together would be
8×b^3
5 0
3 years ago
Read 2 more answers
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
3 years ago
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