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3 years ago

What is the sum of the first 10 terms in this geometric sequence? 3,-6,12,-24

Mathematics

2 answers:

ohaa [14]3 years ago

8 0

3(-2)= -6
-6(-2)= 12
12(-2)= -24
-24(-2)= 48
48(-2)= -96
-96(-2)= 192
192(-2)= -384
-384(-2)= 768
768(-2)= -1536

-1536 is the tenth term in this geo-sequence

lana [24]3 years ago

4 0

3,-6,12,-24,48,-96,192,-384,768,-1536

sum:
3 -6+12 -24+ 48 -96+ 192 -384+ 768 -1536 = -1023

Answer is C. -1023

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$P(\frac{B}{M} ) = 0.3030$

Step-by-step explanation:

Explanation:-

Given data

Brown Blue Hazel Green

Females 13 4 6 9

Males 10 2 9 12

Let 'B' be the event of brown eyes

Total number of males n(M) = 33

Let B/M be the event of randomly selected student from the class has brown eyes given they are male

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = \frac{n(B)}{n(M)}$

From table the brown eyes from males = 10

$P(\frac{B}{M} ) = \frac{10}{33}$

$P(\frac{B}{M} ) = 0.3030$

Final answer:-

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

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tiny-mole [99]

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