For any y-intercept, the x-coordinate is zero. This is something to bear in mind to start with.
Now to find the y-intercept, find g(0) = -2.
Therefore the answer is (0,-2)
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Answer:
C: 18
Step-by-step explanation:
To get the value of n u have to set n by itself, first we have to set teh smallest n to teh other side this will give you 0=8+2n now subtract the 8 from both sides because it is positive and the only way to get rid of a positive is with a negative this will give you -8=2n, now to set n by itself divide by 2 in both sides because in order to get rid of a multiplication you have to divide, this will give you n=-4, so your answer will be letter A
Hope this helps
Answer:
Step-by-step explanation:
alright lets get started.
Please refer the diagram I have attached.
the runner traveled, six kilometers east.
Next, they turn to north and suppose they run x kilometers.
The starting and the ending points distance is 10 kilometers.
There will be a right triangle formed, we can find the value of x by using Pythagorean theorem.
Subtracting 36 from both sides
So, the runners travel 8 kilometers to the north. : answer
Hope it will help. :)
