1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385
The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
-b= 0.5
(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)
-b/-1= 0.5/-1
Therefore b=-0.5
The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10
Hence, c= 0.01
For part A: you will get 3 linear factors (as the degree of the polynomial is 3). perform the division using (x-1) as your known factor and you will get (x-1)(2x²+11x+15). you can then factor the (2x²+11x+15) to get 2x^3 + 9x^2 + 4x - 15 = (x-1)(2x+5)(x+3)
for part B: since 2x+5 will provide the greatest value (assuming x>0) of the 3 factors, then 2x+5=13. solve to get x=4. if x is 4, then the dimensions are 3'x13'x7' [just sub 4 into the x's for each factor]
for part C: as to the graphing calculator, I don't have one. However, if you solve each linear factor for when it is 0, those values will be the x-intercepts. So your graph should cross the x-asix at 1, -5/2, and -3
The z or t score to be used is (0.422,0.978)
How to find the critical value ?
Critical probability (p*) = 1 - (Alpha / 2), where Alpha is equal to 1 - (the confidence level / 100), is the unit statisticians use to determine the margin of error within a set of data in statistics.
The critical value for α = 0.13 is
The corresponding confidence interval is computed as shown below


CI = (0.422, 0.978)
0.422< mu1 - mu 2 < 0.978
To learn more about finding the critical value from the given link
brainly.com/question/14040224
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Answer:
Sides in descending order: YZ > ZX > XY
Step-by-step explanation:
Sum of all angles of triangle = 180
104 +52 + ∠Z = 180
156 + ∠Z = 180
∠Z = 180 - 156
Z = 24
The sides opposite to the biggest is the longest side.
Angles in descending order: ∠X > ∠Y > ∠Z
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Sides in descending order: YZ > ZX > XY</h3>