Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
Answer:
4(4 + x)
Step-by-step explanation:
The only way to factor this expression is to take out the 4
16 + 4x
4(4 + x)
Answer: 4(4 + x)
Answer:
htdxdfdfg
Step-by-step explanation:
First, you need to write out the problem. the sum (which is adding) of 4 times a number ( which we will call n) and 17 is 33. you would write it like this:
(4 x n) + 17 = 33
First, find out what 33 - 17 is. (it's 16)
4 times 4 is 16
(4 x 4) + 17 = 33
16 + 17 = 33
