The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X,
,
, False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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0, 1, 1, 2, 2, 2, 2, 3, 3, 5
minimum: 0
maximum: 5
mean: 2.1
median: 2
mode: 2
I think the data have zero skew. Its mean, median, and mode are based on 2. It shows symmetry.
C - 0.15c is the same as 1c - 0.15c.
1 - 0.15 = 0.85.
Joe can also use 0.85c.