A waterfall has a height of 1400 feet. A pebble is thrown upward from the top of the falls with an initial velocity of 16 feet per second. The height, h, of the pebble after t seconds is given by the equation h equals negative 16 t squared plus 16 t plus 1400
h=−16t2+16t+1400. How long after the pebble is thrown will it hit the ground?
Answer
The pebble hits the ground after 9.8675 s
Step-by-step explanation:
Given
waterfall height = 1400 feet
initial velocity = 16 feet per second
The height, h, of the pebble after t seconds is given by the equation.
The pebble hits the ground when 
---------------(1)
put 
in equation (1)
Divide by -4 to simplify this equation
using the Quadratic Formula where
a = 4, b = -4, and c = -350
The discriminant 
so, there are two real roots.
Use the positive square root to get a positive time.
The pebble hits the ground after 9.8675 second
Can you take that picture again because i cant see.
Answer:
temperature ≤ 6
Step-by-step explanation:
The highest temperature in February was 6°F. Write and graph an inequality to represent this situtation.
If the maximum temperature was 6, then the temperature reached no more than six, while still reaching 6. Thus, the inequality should be
temperature ≤ 6
The graph would be a filled dot on the 6 pointing towards the left side of the graph (towards the -10 side)
Answer:
d(5) = 5
Step-by-step explanation:
The nth term is given by :
...(1)
We need to find the 5th term of the above sequence. For this, put n = 5 in the above formula.
So, the 5th term in the above sequence is 5.
We know,
The slope of the line is given by the ration of chnage of y-cordinate with respect to the ratio of change of x coordinate.
Thus the slope of the given line is:
The slope is 2/1.
