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2 years ago

Type the expression that results from the following series of steps:

Mathematics

1 answer:

Masja [62]2 years ago

5 0

Answer: 6x+y

Step-by-step explanation:

Just convert the words into operations.

Have a nice day! :D

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Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t

schepotkina [342]

Answer:

(A) Set A is linearly independent and spans $R^3$ . Set is a basis for $R^3$ .

Step-by-Step Explanation

Definition (Linear Independence)

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

Definition (Span of a Set of Vectors)

The Span of a set of vectors is the set of all linear combinations of the vectors.

Definition (A Basis of a Subspace).

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors $A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right)$ , we are to decide which of the given statements is true:

In Matrix $A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right)$ , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. $R^3$ has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans $R^3$ .

Therefore Set A is linearly independent and spans $R^3$ . Thus it is basis for $R^3$ .

8 0

3 years ago

Please help me thank you!

Romashka [77]

Answer:

the answer is 1¢26 if not try h5

7 0

2 years ago

describe the transformations that produce the graph of g(x)=1/2(x-4)^3+5 from the graph of the parent function f(x)=x^3. Give th

SSSSS [86.1K]

We have been given a parent function $f(x)=x^{3}$ and we need to transform this function into $g(x)=\frac{1}{2}(x-4)^{3}+5$ .

We will be required to use three transformations to obtain the required function from $f(x)=x^{3}$ .

First transformation would be to shift the graph to the right by 4 units. Upon using this transformation, the function will change to $g(x)=(x-4)^{3}$ .

Second transformation would be to compress the graph vertically by half. Upon using the second transformation, the new function becomes $g(x)=\frac{1}{2}(x-4)^{3}$ .

Third transformation would be to shift the graph upwards by 5 units. Upon using this last transformation, we get the new function as $g(x)=\frac{1}{2}(x-4)^{3}+5$ .

6 0

3 years ago

Here 1 more than BIG PRIZE

Firlakuza [10]

Hey there! :D

Use the distributive property.

a(b+c)= ab+ac

6(9x+2)+2x

54x+12+2x

56x+ 12 <== equivalent expression

I hope this helps!
~kaikers

4 0

3 years ago

Simplify (x^2 -25)/ (2x^2-7x-15)

murzikaleks [220]

Answer:

$\frac{x+5}{2x+3}$