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3 years ago

Solve for the given time.

Mathematics

1 answer:

LenaWriter [7]3 years ago

5 0

Answer:

8851.86

Step-by-step explanation:

100-4.3= 95.7%

15000(.957)^12

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Passes through (8,7) and (0,0)

quester [9]

Answer:

6,3

Step-by-step explanation:

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3 years ago

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Solve 5n – 7p + 3n = 25p for n.

saul85 [17]

5n – 7p + 3n = 25p

Combine like terms

8n - 7p = 25p

Add (7p) to both sides

8n - 7p + 7p = 25p + 7p

Simplifying

8n = 32p

Divide both sides by 8

8n / 8 = 32p / 8

Simplifying

n = 4p

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3 years ago

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Use the Distributive Property to find the Product 4 and 2/5 × 10

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Distributive Property ( A number, n, is multiplied to the expression in parentheses)

$4( \frac{2}{5} \times 10) = \\ 4( \frac{20}{5} ) = \\ 4(4) = 16$

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3 years ago

Quincy uses the quadratic formula to solve for the values of x in a quadratic equation. He finds the solution, in simplest radic

Alexxx [7]

Answer:

<h2>A. Zero, because the discriminant is negative. </h2>

Step-by-step explanation:

I just did it.

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A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$

Hence, our required probability is $\dfrac{1}{2}$

No, the answer is not $\dfrac{1}{3}$

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3 years ago