How do I graph y= 5/6x+1
1 answer:
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Answer:
y²/324 -x²/36 = 1
Step-by-step explanation:
Where (0, ±b) are the ends of the transverse axis and y = ±(b/a)x describes the asymptotes, the equation of the hyperbola can be written as ...
y²/b² -x²/a² = 1
<h3>Application</h3>Here, we have transverse axis endpoints of (0, ±18) and asymptotes of y = ±3x, so we can conclude ...
b = 18
b/a = 3 ⇒ a = 18/3 = 6
The equation of the hyperbola in standard form is ...
y²/324 -x²/36 = 1
Answer:
-1/6
Step-by-step explanation:
flip the slope
becomes
now the slope is going down so it becomes negative
= -1/6
Answer:
Step-by-step explanation:
We want to write the quadratic equation whose roots are 2 and -2, and whose leading coefficient is 4.
Since 2 and -2 are roots, are factors of this quadratic function.
The factored form is given as:
Since the leading coefficient is 4, a=4
Therefore the equation becomes:
Recognize and expand using difference two squares.
The required equation is: