Answer:
question one is 2,251.02
question 2 is 579.58
Step-by-step explanation:
Answer:
9(t+5)<6
t<-13/3
Step-by-step explanation:
The expression is 9(t+5)<6
Distributing the 9, we get
9t+45<6
9t<-39
t<-13/3
Answer:
SSS
Step-by-step explanation:
REM and DME share a side. This side is of course congruent.
In addition, sides RM and ED are marked as congruent, as are RE and MD.
All three corresponding sides of each triangle are congruent, which proves the triangles' congruency.
No information is given about the angles in these triangles, so none of the other theorem answer choices are valid.
Please mark brainliest! :)
Answer:
10 groups you need to make 200.
mark as brainlist
(a) x = 4
First, let's calculate the area of the path as a function of x. You have two paths, one of them is 8 ft long by x ft wide, the other is 16 ft long by x ft wide. Let's express that as an equation to start with.
A = 8x + 16x
A = 24x
But the two paths overlap, so the actual area covered will smaller. The area of overlap is a square that's x ft by x ft. And the above equation counts that area twice. So let's modify the equation by subtracting x^2. So:
A = 24x - x^2
Now since we want to cover 80 square feet, let's set A to 80. 80 = 24x - x^2
Finally, let's make this into a regular quadratic equation and find the roots.
80 = 24x - x^2
0 = 24x - x^2 - 80
-x^2 + 24x - 80 = 0
Using the quadratic formula, you can easily determine the roots to be x = 4, or x = 20.
Of those two possible solutions, only the x=4 value is reasonable for the desired objective.
(b) There were 2 possible roots, being 4 and 20. Both of those values, when substituted into the formula 24x - x^2, return a value of 80. But the idea of a path being 20 feet wide is rather silly given the constraints of the plot of land being only 8 ft by 16 ft. So the width of the path has to be less than 8 ft (the length of the smallest dimension of the plot of land). Therefore the value of 4 is the most appropriate.
