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Kazeer [188]
3 years ago
15

Thank you thank you thank you thank you thank you thank you thank

Mathematics
2 answers:
GuDViN [60]3 years ago
6 0

Answer: yuh

Step-by-step explanation:

yuh

ASHA 777 [7]3 years ago
3 0

Answer:

N = number of guests

N = (150 ± 30)/25

maximum N = 180/25 = 7 maximum

minimum N = 120/25 = 4 minimum

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In a local car lot, 1/6
Black_prince [1.1K]

Answer: \dfrac{5}{324}

Step-by-step explanation:

Given

Probability that car has a standard transmission is \frac{1}{6}

So, the probability that the car does not have transmission is

1-\dfrac{1}{6}=\dfrac{5}{6}

Probability of that 3 out of 4 randomly selected cars have standard transmissions is given by selecting 3 cars with standard deviation and then multiply by their respective probabilities

\Rightarrow P=^4C_3\cdot \left(\dfrac{1}{6}\right)^3\cdot \left(\dfrac{5}{6}\right)\\\\\Rightarrow P=4\times\dfrac{5}{6^4}\\\\\Rightarrow P=\dfrac{20}{1296}\\\\\Rightarrow P=\dfrac{5}{324}

7 0
2 years ago
Help meeeeeeeeeeeeeeeeeeeeeeeeeee
MariettaO [177]

Answer:

*These Should be the correct answers*

1.C

2.D

Step-by-step explanation:

7 0
1 year ago
What is the equation of the line that is parallel to the line 2x+3y=-8 and passes through the point (2,-2)?
Leya [2.2K]

Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is y=\frac{-2 x}{3}+\frac{-2}{3}

<h3><u>Solution:</u></h3>

Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)

Generic slope intercept form of a line is given by y = mx + c

where "m" = slope of the line and "c" is the y - intercept

Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

\begin{array}{l}{2 x+3 y=-8} \\\\ {=>y=\frac{-2 x-8}{3}} \\\\ {\Rightarrow y=-\frac{2}{3} x-\frac{8}{3}}\end{array}

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

\text {for line } 2 x+3 y=-8, \text { slope } m=-\frac{2}{3}

We know that slopes of parallel lines are always equal

So the slope of line passing through (2, -2) is also m=-\frac{2}{3}

Equation of line passing through (x_1 , y_1) and having slope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=2 \text { and } y_{1}=-2

Substituting the values in equation of line we get

(y-(-2))=-\frac{2}{3}(x-2)

\begin{array}{l}{\Rightarrow y+2=\frac{-2 x+4}{3}} \\\\ {=>3(y+2)=-2 x+4} \\\\ {=>3 y+6=-2 x+4} \\\\ {3 y=-2 x-2}\end{array}

y=\frac{-2 x}{3}+\frac{-2}{3}

Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as y=\frac{-2 x}{3}+\frac{-2}{3}

7 0
3 years ago
Solve the equation 6(2x+4)^2=(2x+4)+2 a x=-5/3 or -9/4
9966 [12]

Answer:

x=5/3

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!!!!
Vesna [10]

(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =

= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}

= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}

= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}

= 2^{-16-12+28} \times 5^{10-8}

= 2^{0} \times 5^{2}

= 1 \times 25

= 25

7 0
2 years ago
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