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3 years ago

15

Thank you thank you thank you thank you thank you thank you thank

2 answers:

GuDViN [60]3 years ago

6 0

Answer: yuh

Step-by-step explanation:

yuh

ASHA 777 [7]3 years ago

3 0

Answer:

N = number of guests

N = (150 ± 30)/25

maximum N = 180/25 = 7 maximum

minimum N = 120/25 = 4 minimum

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In a local car lot, 1/6

Black_prince [1.1K]

Answer: $\dfrac{5}{324}$

Step-by-step explanation:

Given

Probability that car has a standard transmission is $\frac{1}{6}$

So, the probability that the car does not have transmission is

$1-\dfrac{1}{6}=\dfrac{5}{6}$

Probability of that 3 out of 4 randomly selected cars have standard transmissions is given by selecting 3 cars with standard deviation and then multiply by their respective probabilities

$\Rightarrow P=^4C_3\cdot \left(\dfrac{1}{6}\right)^3\cdot \left(\dfrac{5}{6}\right)\\\\\Rightarrow P=4\times\dfrac{5}{6^4}\\\\\Rightarrow P=\dfrac{20}{1296}\\\\\Rightarrow P=\dfrac{5}{324}$

7 0

2 years ago

Help meeeeeeeeeeeeeeeeeeeeeeeeeee

MariettaO [177]

Answer:

*These Should be the correct answers*

1.C

2.D

Step-by-step explanation:

7 0

1 year ago

What is the equation of the line that is parallel to the line 2x+3y=-8 and passes through the point (2,-2)?

Leya [2.2K]

Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is $y=\frac{-2 x}{3}+\frac{-2}{3}$

<h3><u>Solution:</u></h3>

Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)

Generic slope intercept form of a line is given by y = mx + c

where "m" = slope of the line and "c" is the y - intercept

Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

$\begin{array}{l}{2 x+3 y=-8} \\\\ {=>y=\frac{-2 x-8}{3}} \\\\ {\Rightarrow y=-\frac{2}{3} x-\frac{8}{3}}\end{array}$

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

$\text {for line } 2 x+3 y=-8, \text { slope } m=-\frac{2}{3}$

We know that slopes of parallel lines are always equal

So the slope of line passing through (2, -2) is also $m=-\frac{2}{3}$

Equation of line passing through $(x_1 , y_1)$ and having slope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=2 \text { and } y_{1}=-2$

Substituting the values in equation of line we get

$(y-(-2))=-\frac{2}{3}(x-2)$

$\begin{array}{l}{\Rightarrow y+2=\frac{-2 x+4}{3}} \\\\ {=>3(y+2)=-2 x+4} \\\\ {=>3 y+6=-2 x+4} \\\\ {3 y=-2 x-2}\end{array}$

$y=\frac{-2 x}{3}+\frac{-2}{3}$

Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as $y=\frac{-2 x}{3}+\frac{-2}{3}$

7 0

3 years ago

Solve the equation 6(2x+4)^2=(2x+4)+2 a x=-5/3 or -9/4

9966 [12]

Answer:

x=5/3

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

WILL GIVE BRAINLIEST!!!!

Vesna [10]

$(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =$

$= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}$

$= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}$

$= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}$

$= 2^{-16-12+28} \times 5^{10-8}$

$= 2^{0} \times 5^{2}$

$= 1 \times 25$

$= 25$

7 0

3 years ago