Solve |x + 2| = 10 3 options

What is the range of the function f(x) = (x - 1)? when the domain is {-5, 0,5}?

Nimfa-mama [501]

Answer:

f(x) = (x - 1)2

f(x) = 2x - 2

let x = -5, f(x) = -12

let x = 0, f(x) = -2

let x = 5, f(x) = 8

range is {-12, -2, 8}

7 0

2 years ago

Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .

By definition, this procedure proves that $\lim_{x\to 5}f(x) = 14$ . Note that f(5)=14, so this proves that f is continous at x=5.

3 0

3 years ago

The money collected from selling bacon at a butcher store is given by the function f(x) = 3.55x – 4, where f(x) is the sales rev

Helga [31]

Answer:

See below under "Explanation".

General Formulas and Concepts:
Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions

Function Notation

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle f(x) = 3.55x - 4$

$\displaystyle x = \{ 17, 21, 24, 34 \}$

Step 2: Find Profit

To find the profit the store makes each day, we input the number of customers that visited the store each day into our given function:

For the day that had 17 customers:

$\displaystyle\begin{aligned}f(17) & = 3.55(17) - 4 \\& = 60.35 - 4 \\& = \boxed{56.35} \\\end{aligned}$

∴ the butcher store made $56.35 when 17 customers visited the store.

For the day that had 21 customers:

$\displaystyle\begin{aligned}f(21) & = 3.55(21) - 4 \\& = 74.55 - 4 \\& = \boxed{70.55} \\\end{aligned}$

∴ the butcher store made $70.55 when 21 customers visited the store.

For the day that had 24 customers:

$\displaystyle\begin{aligned}f(24) & = 3.55(24) - 4 \\& = 85.2 - 4 \\& = \boxed{81.2} \\\end{aligned}$

∴ the butcher store made $81.20 when 24 customers visited the store.

For the day that had 34 customers:

$\displaystyle\begin{aligned}f(34) & = 3.55(34) - 4 \\& = 120.7 - 4 \\& = \boxed{116.7} \\\end{aligned}$

∴ the butcher store made $116.70 when 34 customers visited the store.

---

Learn more about functions: brainly.com/question/27710450

Learn more about Algebra I: brainly.com/question/27710380

---

Topic: Algebra I

3 0

2 years ago

Subtract the equation m-3n/6m3n - m+3n/6m^3n

Sergio039 [100]

Answer:

- n^2m(3 - m^2)/2

3 0

3 years ago

Tessa bought stock in a restaurant for $151.00. Her stock is now worth $196.30. What is the percentage increase of the value of

goldenfox [79]

I believe the answer is C. I’m terribly sorry if I got it wrong

7 0

3 years ago