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geniusboy [140]
3 years ago
7

When x= -1, what is the value of y?

Mathematics
1 answer:
solmaris [256]3 years ago
4 0

Answer:You need to give a equation first.

Step-by-step explanation:Equation please!

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Consider the expression below
brilliants [131]
This one is my real answer 5{10+3]=40 The other one you can use for extra this one 5{10+25]=35

4 0
3 years ago
Write an ordered pair for the point
aleksandr82 [10.1K]

Answer:

(0, 1)

Step-by-step explanation:

The point lies on the line x = 0.

The point lies on the line y = 1.

Where both lines intersect, that is the coordinate.

(x, y)

(0, 1)

5 0
4 years ago
Read 2 more answers
What equals 39 by multiplying 10 ?
qwelly [4]

You can just do the inverse operation. 39 divied by 10 = 3.9

so 3.9 *10 =39

hope it helped

5 0
3 years ago
A pet store sells goldfish and hermit crabs,
Elis [28]

Answer:

Cost = \$28

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

7g + 3h = 26

The second statement, we have:

4g + 5h = 28

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

7g + 3h = 26 --- (1)

4g + 5h = 28 --- (2)

Make g the subject in (2)

4g + 5h = 28

4g = 28 - 5h

Divide both sides by 4

g = \frac{1}{4}(28 - 5h)

Substitute \frac{1}{4}(28 - 5h) for g in (1)

7g + 3h = 26

7(\frac{1}{4}(28 - 5h)) + 3h = 26

\frac{7}{4}(28 - 5h) + 3h = 26

Multiply through by 4

4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4

7(28 - 5h) + 4*3h = 26*4

Open bracket

196 - 35h + 12h = 104

196 -23h = 104

Collect Like Terms

-23h = 104-196

-23h = -92

Make h the subject

h = \frac{-92}{-23}

h = \frac{92}{23}

h = 4

Substitute 4 for h in g = \frac{1}{4}(28 - 5h)

g = \frac{1}{4}(28 - 5*4)

g = \frac{1}{4}(28 - 20)

g = \frac{1}{4}(8)

g = 2

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

Cost = 6g + 4h

Cost = 6*\$2 + 4*\$4

Cost = \$12 + \$16

Cost = \$28

5 0
3 years ago
Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6
crimeas [40]

Answer:

  c.  3a^2b^11/2

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)/(a^c) = a^(b-c)

__

 \dfrac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}=\dfrac{-18}{-12}a^{-2-(-4)}b^{5-(-6)}=\boxed{\dfrac{3a^2b^{11}}{2}}

3 0
2 years ago
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