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faust18 [17]
3 years ago
15

Find the value of 6^-3​

Mathematics
2 answers:
lana66690 [7]3 years ago
3 0

Answer:

\frac{1}{216}

Step-by-step explanation:

→ First calculate 6⁻³

216

→ Remember that negative indices results in the reciprocal

\frac{1}{216}

postnew [5]3 years ago
3 0

Answer:

-216

Step-by-step explanation:

6-³

=1/6³ (exponential property)

1/6×6×6

=1/216

=-216

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We are given

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4 0
3 years ago
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1) Is y=-3 a solution to the equation-3x^2=-27
sergey [27]

Answer:

1)Yes

2)No

Step-by-step explanation:

1) 3x^2 = -27

3 (-3)^2 = -27

Once you substitute your value in for x, you can follow the rule <u>PEMDAS</u> to solve the equation.

3 (-9) = -27

-27 =-27

2) 10 - 5x = y

In an ordered pair, the first number is x and the second number is y.

10 - 5 (-4) = 10

10 - 20 = 10

-10 = 10

-10 ≠ 10

PEMDAS: A rule that states solving an equation by the order of operations:

Parentheses

Exponents

Multiplication

Division

Addition

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8 0
3 years ago
Which line is parallel to the line y=12x+5 and passes through the point (-2, 1)?
Nostrana [21]
Hello : 
this line has same slope with the line : y=12x+5
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3 0
4 years ago
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How do u find the volume of a cylinder?<br><br><br><br><br> Look at comment under question
Temka [501]

Answer:

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8 0
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The answer is c, but I'm stuck between b and c​
Ilia_Sergeevich [38]

We have q < 0 < p < -r

Since q < 0, this means q is some negative number. The ordered pair (x,y) = (2,q) tells us that the point is below the x axis when x = 2. This does not fit graph B because it appears that an x intercept is at x = 2 (though the graph is a bit small so please provide larger versions of each graph if possible).

This does fit graph C because this point is below the x axis when x = 2.

-----------

Then we have 0 < p or p > 0. So p is some positive number. The point (4,p) is some point above the x axis. We started with (2,q) being below the x axis and now we're above the x axis at (4,p). Only graph C fits this description.

Finally p < -r, so -r is some positive number larger than p. Therefore r itself is some negative number. Example: r = -10, -r = -(-10) = 10.

This means the point (6,r) is below the x axis. Once again this fits the description of what graph C is showing.

----------

<h3>So that is why graph C is the final answer.</h3>

Graphs A and D are ruled out because there is no transition from positive to negative or vice versa. Graph B is ruled out because of the x intercept at 2 (when that point should be below the x axis); however, the graph is a bit small so please provide a larger copy if possible. Thank you.

8 0
3 years ago
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