Answer: 1
Step-by-step explanation: 1. 4x4=16 4x4x4= -64x16= -1024
A) (1, 7) Doesn't
B) (0, 4) Doesn't
C) (2, –2) Doesn't
D) (3, –5) DOES
All the steps are right at the exception of line 7 (and onwards)
line 6 : 6x = 42 (it's right). Now divide both sides by 6:
line 7 should be: 6x/6 = 42/6
line 8 should be: x = 7.
Answer:
(7, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
x = 2y + 5
x/3 - y = 4/3
<u>Step 2: Solve for </u><em><u>y</u></em>
- Substitute: (2y + 5)/3 - y = 4/3
- Multiply 3 on both sides: 2y + 5 - 3y = 4
- Combine like terms: -y + 5 = 4
- Isolate <em>y</em> term: -y = -1
- Isolate <em>y</em>: y = 1
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define: x = 2y + 5
- Substitute: x = 2(1) + 5
- Multiply: x = 2 + 5
- Add: x = 7
And we have our final answer!
-- The difference of 2 logs is the log of the quotient of their arguments.
log(11) - log(6) = log(11/6)
-- 1/3 of the log of something is the log of its cube root.
1/3 log(8) = log(∛8) = log(2)
and
1/3 log(729) = log(∛729) = log(9)
-- If a bunch of logs all have the same base, then their sum
is the log of the product of the arguments. So ...
log(11) - log(6) + 1/3 log(8) + 1/3 log(729) =
log(11/6 times 2 times 9) =
log( 11*18 / 6 ) = <em>log(33)</em>
log(33) = about <em>1.519</em> (rounded)
============================================
The other way:
log(11) = 1.0414
-log(6) = -0.7782
log(8) = 0.9031
1/3(0.9031) = 0.3010
log(729) = 2.8627
1/3(2.8627) = 0.9542
-----------
Adum up: <em>1.5184</em>
(Note: Everything is rounded.)
Answer:
A
Step-by-step explanation:
