What time is 90° counterclockwise?

Please help me out!

valina [46]

Answer:

4/11=.363636....

I hope this is good enough:

6 0

3 years ago

In a large section of a statistics class, the points for the final exam are normally distributed, with a mean of 71 and a stan

kumpel [21]

Answer:

The lowest score on the final exam that would qualify a student for an A is 80.

The lowest score on the final exam that would qualify a student for a B is 74.68.

The lowest score on the final exam that would qualify a student for a C is 67.33.

The lowest score on the final exam that would qualify a student for a D is 62.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 71 and a standard deviation of 7.

This means that $\mu = 71, \sigma = 7$

Grades are assigned such that the top 10% receive A's, the next 20% received B's, the middle 40% receive C's, the next 20% receive D's, and the bottom 10% receive F's.

This means that:

90th percentile and above: A

70th percentile and below 90th: B

30th percentile to the 70th percentile: C

10th percentile to the 30th: D

Lowest score for an A:

Top 10% receive A, which means that the lowest score that would qualify a student for an A is the 100 - 10 = 90th percentile, which is X when Z has a pvalue of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 71}{7}$

$X - 71 = 7*1.28$

$X = 80$

The lowest score on the final exam that would qualify a student for an A is 80.

Lowest score for a B:

70th percentile, which is X when Z has a pvalue of 0.7, so X when Z = 0.525.

$Z = \frac{X - \mu}{\sigma}$

$0.525 = \frac{X - 71}{7}$

$X - 71 = 7*0.525$

$X = 74.68$

The lowest score on the final exam that would qualify a student for a B is 74.68.

Lowest score for a C:

30th percentile, which is X when Z has a pvalue of 0.3, so X when Z = -0.525.

$Z = \frac{X - \mu}{\sigma}$

$-0.525 = \frac{X - 71}{7}$

$X - 71 = 7*(-0.525)$

$X = 67.33$

The lowest score on the final exam that would qualify a student for a C is 67.33.

Lowest score for a D:

10th percentile, which is X when Z has a pvalue of 0.1, so X when Z = -1.28.

$Z = \frac{X - \mu}{\sigma}$

$-1.28 = \frac{X - 71}{7}$

$X - 71 = 7*(-1.28)$

$X = 62$

The lowest score on the final exam that would qualify a student for a D is 62.

4 0

3 years ago

An isosceles triangle can be scalene true or false?

Naddika [18.5K]

Answer: False according to apex

Step-by-step explanation:

5 0

3 years ago

Simplify. (-2)^-3<br><br> PLEASE HELP

nika2105 [10]

You have a negative exponent so you have to bring the -2 down : 1/-2^3. Then you multiply the -2*-2*-2 which is -8 so you get 1/-8 or -1/8. It means the same thing.

4 0

3 years ago

Read 2 more answers

What is the area of a rectangle with vertices at (0, −4) , (−1, −3) , (2, 0) , and (3, −1) ? Enter your answer in the box

Bad White [126]

We are given vertices of a rectangle (0, −4) , (−1, −3) , (2, 0) , and (3, −1).

Length is the distance between (0, −4) and (−1, −3) points.

Width is distance between (−1, −3) and (2, 0) points.

<u>Computing length:</u>

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$