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Marianna [84]
3 years ago
9

PLEASE HELPP DUE TODAYYYY:what is the LDC least common denominator

Mathematics
1 answer:
boyakko [2]3 years ago
4 0
I believe the least common denominator is six.
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What is the whole nunnery 13,260,000in expanded form?
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Step-by-step explanation:

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Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.
Hitman42 [59]
\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
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sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
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sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\

\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
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sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
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\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
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\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
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\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
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\textit{and now, let's rationalize the denominator}
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\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}

7 0
3 years ago
Which number line shows the solution for
Brums [2.3K]

Answer:

It's the last choice.

Step-by-step explanation:

| n | ≤ 2  represents the distance between n and 0 that is less than or equal to 2.  The dots on the 2 and -2 are black because the equal sign is part of the inequality.

Note the vertical lines about the n mean the absolute value of n - the positive distance between  n and 0, which has a maximum of 2 either side of the 0.

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