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Marianna [84]
3 years ago
9

PLEASE HELPP DUE TODAYYYY:what is the LDC least common denominator

Mathematics
1 answer:
boyakko [2]3 years ago
4 0
I believe the least common denominator is six.
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A sweater is on sale for 30% off the ticketed price of $84. How much will the sweater cost after the discount?
Marianna [84]
84 x .70 = $58.80

Or if you want to do it the long way you can calculate the actual discount (your savings from this purchase first then subtract it from the original price of $84. It`s just easier to figure out what is left (which is 70% of $84).
3 0
4 years ago
HELPPP PLZ I WILL GIVE 15囧rz and brainliest
kati45 [8]

Answer:

you are a lie you said you will give 15 points and its only 8

Step-by-step explanation:

6 0
3 years ago
Help and explain how you got it.<br><br> no trolling or report!
Galina-37 [17]

Answer:

I am 100% confident in my calculations. I'm not 100% sure about interpreting. Sorry I can't be of more help.

Part A:

Median: 4.5

IQR: 3.5

Mode: 6

I think the median/IQR is a better measure of center and variability because the range of data is so big (10 - 0 = 10), and the data skews to the right with the 6s.

Part B:

I would say no. It is the one that occurs most frequently, but there are many more times she rides less than 6, which is why the median is 4.5

Step-by-step explanation:

Mean: 4.714

MAD: 2.43

Median: 4.5

IQR: 3.5

Mode: 6

the number set in order:

0, 2, 2, 2.5, 2.5, 3, 4, 5, 6, 6, 6, 8, 9, 10

The median (middle number) is two numbers: 4 and 5, so the median is 4.5

The first quartile/Q1 (middle of the bottom half of data) is 2.5, the third quartile/Q3 (middle of the top half of data) is 6. So the IQR (interquartile range) is 6 - 2.5 = 3.5

The mean is the sum of the numbers divided by the quantity of the numbers, so 66/14 = 4.714

the mean absolute deviation is found by calculating the mean, and then finding the absolute value of the difference between each number of the set and the mean...then adding those together and finding the mean of that set. Labor intensive, but that's 34/14 = 2.42857143

4 0
3 years ago
Sam is 6 years older than marlon. The sum of their ages is 30. Find Sam and marlons age.
Triss [41]

Answer:

Sam = 18 and Marlon = 12

Step-by-step explanation:

If Sam is 6 years older but added is 30 then Sam could 18 and Marlon 12.

6 0
4 years ago
Read 2 more answers
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
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