A 4500.00 g bowling ball rolling at a 4.0m/s I NEED HELPPP ASAPPP

Does - 3/4 + 3/5 have a positive, negative or zero sum?

ryzh [129]

are you looking for the answer??

4 0

3 years ago

A small farm field is a square measuring 320 ft on a side. What is the perimeter of the field? If you double the length of each

Marina CMI [18]

Answer:

old per: 1280

new per:2560

Step-by-step explanation:

first perimeter u get it by adding all the sides and since its a square then all the sides are equal so u can just do

320*4 which is equal to 1280

and by doubling the sides u can just double it in the old equation meaning

(320*2)*4

which is equal to 2560

6 0

3 years ago

Read 2 more answers

Find the equation of the line.

zhuklara [117]

Answer:

y=-1/3x-2

Step-by-step explanation:

First off, lets outline that parallel lines have the <u>Same Slope</u>. So we can plug in -1/3 as our slope, or m.

Lets plug in -1/3 as our slope in Point Slope form to find the y intercept. Point slope form should be attached in an image below.

1) Plug slope and points into point slope form:

y+1=-1/3(x+3)

2) Distribute -1/3 to x and 3:

y+1=-1/3x-1

3) Subtract 1 from both sides:

y=-1/3x-2

Now we have our answer is slope intercept form!

Please let me know if you have any questions :)

3 0

3 years ago

Simplify 7N - 2N + 3P + 2P. (a) 5N + 5P (b) 10N + 10P (c)10NP

Yakvenalex [24]

<span>7N - 2N + 3P + 2P

Combine like terms:
7N-2N=5N

3P+2P=5P

Put them together to get :
5N+5P

Final answer:
A</span>

7 0

3 years ago

Read 2 more answers

The base of an aquarium with given volume V is made of slate and the sides are made of glass. If slate costs five times as much

Y_Kistochka [10]

Answer:

x = ∛ 2*V/5

y = ∛ 2*V/5

h = V/ ∛ 4*V²/25

Step-by-step explanation:

Dimensions of the aquarium base is x*y

We call c₁ cost per unit area of the sides, then cost per unit area of slate is equal 5c₁.

let call h the height of the aquarium then volume of the aquarium is:

V = x*y*h where h = V / x*y

As the base is a rectangular one there are 2 sides x*h . and 2 sides y*h

According to this:

Ct (cost of aquarium ) = cost of the base + cost of the sides

cₐ ( cost of the base) = 5*c₁*x*y

c₆ (cost of the sides ) = c₁*2*x*h + c₁*2*y*h

C(t) = 5*c₁*x*y +2* c₁*x* V/x*y + 2* c₁*y* V/x*y or

C(t) = 5*c₁*x*y + 2*c₁*V/y *2*c₁* V/x

Taking partial derivatives en x and y we have:

C´(x) = 5*c₁*y - 2*c₁*V/x²

C´(y) = 5*c₁*x - 2*c₁*V/y²

C´(x) = C´(y) ⇒ 5*c₁*y - 2*c₁*V/x² = 5*c₁*x - 2*c₁*V/y²

or 5*y - 2*V/x² = 5*x - 2*V/y²

(5*y*x² - 2*V)/x² = ( 5*y²x - 2*V) /y²

(5*y*x² - 2*V)*y² = ( 5*y²x - 2*V)*x²

5*y³*x² - 2*V*y² = 5*y²x³ - 2*V*x²

5*y³*x² - 5*y²x³ = 2*V * ( y² - x²)

by symmetry x = y

Then using x = y and plugging that value on the derivatives

C´(x) = 5*c₁*y - 2*c₁*V/x²

C´(x) = 5*c₁*x - 2*c₁*V/x²

C´(x) = 0 ⇒ 5*c₁*x - 2*c₁*V/x² = 0

5*x - 2*V/x² = 0 ⇒ 5*x³ - 2*V = 0 ⇒ 5*x³ = 2*V ⇒ x³ = 2*V/5

x = ∛ 2*V/5 and y = ∛ 2*V/5 and h = V/ x*y h = V/ ∛ 4*V²/25

7 0

3 years ago