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sattari [20]
2 years ago
13

Kyra observed that 85% of the students at a library liked reading mystery stories. If 30 students at the library did not like re

ading mystery stories, the number of students at the library who liked mystery stories was _____. (only put numeric values, no other symbols) Numerical Answers Expected!
Mathematics
1 answer:
UkoKoshka [18]2 years ago
6 0
It is said that 85% of the students liked reading mystery stories. This means the remaining 15% don't like to read these stories. If there are 30 students belonging to the second category, then the number of students who liked reading mystery stories is (30/0.15)*0.85 equal to 170 students out of 200 students.
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The following data points are the number of chocolate chips in 4 different chocolate chip cookies in a
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Standard Deviation, σ: 1.870828693387

Count, N: 4
Sum, Σx: 12
Mean, μ: 3
Variance, σ2: 3.5
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3 years ago
Write an equation in standard form using integers <br><br> Y= - x<br> —<br> 5
kykrilka [37]

Answer:

x + y = - 5

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = - x - 5 ( add x to both sides )

x + y = - 5 ← in standard form

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3 years ago
Sarah claims that the thickness of the spearmint gum she produces is 7.5 one-hundredths of an inch. A quality control specialist
satela [25.4K]

Answer:

t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539    

p_v =2*P(t_{(9)}>1.539)=0.158  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis.  

Step-by-step explanation:

Data given and notation  

Data: 7.65, 7.60, 7.65, 7.7, 7.55, 7.55, 7.4, 7.4, 7.5, 7.5

We can begin calculating the sample mean given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And the sample deviation given by:

s=\sart{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And we got:

\bar X=7.55 represent the sample mean

s=0.103 represent the sample standard deviation

n=10 sample size  

\mu_o =7.5 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 7.5 or no, the system of hypothesis would be:  

Null hypothesis:\mu = 7.5  

Alternative hypothesis:\mu \neq 7.5  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=10-1=9  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(9)}>1.539)=0.158  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis.  

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3 years ago
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Answer:

He has food for 9 days.

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Step-by-step explanation:

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If m&lt;3 = 54° find each measure.
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Answer:

m<15

Step-by-step explanation:

m<15 promise ko heheh

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2 years ago
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