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Cerrena [4.2K]
3 years ago
5

Which exponential function is represented by the values in the table?

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

\displaystyle f(x)=4\cdot\left(\frac{1}{2}\right)^x

Step-by-step explanation:

<u>Exponential Function</u>

The exponential function can be written with the general equation:

f(x)=A\cdot r^x

Where A is the value when x=0 and r>0 is the ratio. If r is greater than 1, the function is increasing, if r is less than 1, the function is decreasing.

The table shows the relation between values of x and values of the function y. Note that as x increases (one by one), y decreases with a ratio of 1/2. Only the last two choices have ratios of r=1/2. We only have to test which one of them has the correct value of y=4 when x=0.

Substituting in the third function:

\displaystyle f(x)=4\cdot\left(\frac{1}{2}\right)^x

\displaystyle f(0)=4\cdot\left(\frac{1}{2}\right)^0

f(0) = 4

This gives the correct value of f(0)=4.

Substituting in the fourth function:

\displaystyle f(x)=\frac{1}{2}\cdot\left(\frac{1}{2}\right)^x

\displaystyle f(0)=\frac{1}{2}\cdot\left(\frac{1}{2}\right)^0

f(0) = \frac{1}{2}

This choice is wrong

Correct choice:

\boxed{\displaystyle f(x)=4\cdot\left(\frac{1}{2}\right)^x}

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Find the equation of ellipse passing throgh (1,4) and (-3,2)​
irinina [24]

Answer:

\displaystyle  \frac{  {3x}^{2} }{ 35 }  +  \frac{{2y}^{2} }{  35  }   = 1

Step-by-step explanation:

we want to figure out the ellipse equation which passes through <u>(</u><u>1</u><u>,</u><u>4</u><u>)</u><u> </u>and <u>(</u><u>-</u><u>3</u><u>,</u><u>2</u><u>)</u>

the standard form of ellipse equation is given by:

\displaystyle  \frac{(x - h {)}^{2} }{ {a}^{2} }  +  \frac{(y - k {)}^{2} }{ {b}^{2} }  = 1

where:

  • (h,k) is the centre
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since the centre of the equation is not mentioned, we'd assume it (0,0) therefore our equation will be:

\displaystyle  \frac{  {x}^{2} }{ {a}^{2} }  +  \frac{{y}^{2} }{ {b}^{2} }  = 1

substituting the value of x and y from the point (1,4),we'd acquire:

\displaystyle  \frac{ 1}{ {a}^{2} }  +  \frac{16}{ {b}^{2} }  = 1

similarly using the point (-3,2), we'd obtain:

\displaystyle  \frac{ 9}{ {a}^{2} }  +  \frac{4 }{ {b}^{2} }  = 1

let 1/a² and 1/b² be q and p respectively and transform the equation:

\displaystyle  \begin{cases} q  +  16p  = 1  \\ 9q + 4p = 1 \end{cases}

solving the system of linear equation will yield:

\displaystyle  \begin{cases} q   =  \dfrac{3}{35} \\ \\  p =  \dfrac{2}{35}  \end{cases}

substitute back:

\displaystyle  \begin{cases}  \dfrac{1}{ {a}^{2} }   =  \dfrac{3}{35} \\ \\   \dfrac{1}{ {b}^{2} }  =  \dfrac{2}{35}  \end{cases}

divide both equation by 1 which yields:

\displaystyle  \begin{cases}  {a}^{2}   =  \dfrac{35}{ 3} \\ \\    {b}^{2}   =  \dfrac{35}{2}  \end{cases}

substitute the value of a² and b² in the ellipse equation , thus:

\displaystyle  \frac{  {x}^{2} }{  \dfrac{35}{3}  }  +  \frac{{y}^{2} }{  \dfrac{35}{2}  }   = 1

simplify complex fraction:

\displaystyle  \frac{  {3x}^{2} }{ 35 }  +  \frac{{2y}^{2} }{  35  }   = 1

and we're done!

(refer the attachment as well)

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Answer:

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Step-by-step explanation:

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The only factor that both terms have is d
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velikii [3]

Answer:

Step-by-step explanation.

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Answer:

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Step-by-step explanation:

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