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Cerrena [4.2K]
3 years ago
5

Which exponential function is represented by the values in the table?

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

\displaystyle f(x)=4\cdot\left(\frac{1}{2}\right)^x

Step-by-step explanation:

<u>Exponential Function</u>

The exponential function can be written with the general equation:

f(x)=A\cdot r^x

Where A is the value when x=0 and r>0 is the ratio. If r is greater than 1, the function is increasing, if r is less than 1, the function is decreasing.

The table shows the relation between values of x and values of the function y. Note that as x increases (one by one), y decreases with a ratio of 1/2. Only the last two choices have ratios of r=1/2. We only have to test which one of them has the correct value of y=4 when x=0.

Substituting in the third function:

\displaystyle f(x)=4\cdot\left(\frac{1}{2}\right)^x

\displaystyle f(0)=4\cdot\left(\frac{1}{2}\right)^0

f(0) = 4

This gives the correct value of f(0)=4.

Substituting in the fourth function:

\displaystyle f(x)=\frac{1}{2}\cdot\left(\frac{1}{2}\right)^x

\displaystyle f(0)=\frac{1}{2}\cdot\left(\frac{1}{2}\right)^0

f(0) = \frac{1}{2}

This choice is wrong

Correct choice:

\boxed{\displaystyle f(x)=4\cdot\left(\frac{1}{2}\right)^x}

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Answer:

Option (3)

Step-by-step explanation:

Properties for the vertical stretch or shrink of a function,

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1). Function will be vertically stretched if k > 1

2). Function will have a vertical shrink if 0 < k < 1

To fit the given data graph of f(x) = |x| will vertically shrink without any translation along x or y-axis.

And the value of k will be, 0 < k < 1.

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Madison needs to buy enough meat to make 1,000 hamburgers for the company picnic. Each hamburger will weigh 0.25 pound. How many
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Madison needs to buy 250 pound of meat

Step-by-step explanation:

6 0
2 years ago
A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha
s2008m [1.1K]

Answer:

Part 1) The  lateral area of the cone is LA=2\pi\ cm^{2}

Part 2) The lateral surface area of the cylinder is LA=36\pi\ cm^{2}

Part 3) The surface area of the crayon is SA=41.50\pi\ cm^{2}

Step-by-step explanation:

Part 1) Find the  lateral area of the cone  

The lateral area of the cone is equal to

LA=\pi rl

we have

r=1\ cm

l=2\ cm

substitute

LA=\pi (1)(2)

LA=2\pi\ cm^{2}

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

LA=2\pi rh

we have

r=1.5\ cm

h=12\ cm

substitute

LA=2\pi (1.5)(12)

LA=36\pi\ cm^{2}

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

<em>Find the area of the bottom base of the crayon</em>

A=\pi[r2^{2}-r1^{2}]

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

A=\pi[1.5^{2}-1^{2}]

A=1.25\pi\ cm^{2}

<em>Find the area of the top base of the cylinder</em>

A=\pi(1.5)^{2}=2.25\pi\ cm^{2}

<em>Find the surface area</em>

SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}

8 0
3 years ago
Read 2 more answers
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