Answer:
so idc![\sqrt[n]{x} \sqrt{x} \alpha \pi x^{2} \\ \left \{ {{y=2} \atop {x=2}} \right. x_{123} \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%5Csqrt%7Bx%7D%20%5Calpha%20%5Cpi%20x%5E%7B2%7D%20%5C%5C%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20x_%7B123%7D%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D)
443
Step-by-step explanation: its 2 6\7
In a water molecule<span>, the </span>oxygen<span> atom and </span>hydrogen<span> atoms share electrons in covalent bonds, but the sharing isn't equal. ... The unequal sharing of electrons gives the </span>water molecule<span> a little bit of a negative charge near its </span>oxygen<span> atom and a slight positive charge near its </span>hydrogen<span> atoms.</span>
Answer:
Step-by-step explanation:
hello :
16t²+120 = y
16t² = y -120 so : t² = (y-120)/16
if : y-120 ≥ 0 t = ±√((y-120)/16)
Answer:
-450
-90
270
Step-by-step explanation: Just did it on edgen-uity
Answer:
The answer is 43 and 19 over 21
Step-by-step explanation:
21 goes into 922 43 times. This giving you 903. 43 Will then be your Whole number. You the subtract 922 by 903, this giving you 19. 19 is going to be your numerator. Then you always keep the denomonator which is 21. This giving you 43 and 19 over 21
