Whatever% of anything is just (whatever/100) * anything.
x = ounces of 14% iodine.
y = ounces of 29% iodine.
we know that in a 14% iodine solution, 14% is iodine and the rest is something else, we also know that "x" ounces of the solution have 14% of iodine, how much is that? (14/100) * x, or 0.14x.
likewise, in the 89 ounces of 47% solution there is (47/100) * 89 of iodine.
and likewise as well, in "y" ounces of 29% iodine there is (29/100) * y, or 0.29y of iodine.
bearing in mind that, whatever "x" and "y" may be, x + 89 = y, and that the sum of the iodine amounts also will equate 0.29y.
Answer:
Step-by-step explanation:
Several trig identities are involved in the proof of this. This is the order in which they are used.
- cos(2x) = cos²(x) -sin²(x)
- cos²(x) +sin²(x) = 1
- cos(x) = 1/sec(x)
<h3>Proof</h3>
Starting with the left side, we can transform it into the right side.

Answer:
smh
Step-by-step explanation:
too ez is the answer is 12421418258475172583521838716523/12312313123651253612534
-12 * 2 is -24, and any number can be added to 2.
(4(2)=8*8*8=512÷6=85.333333
(4-2)=2
8-2=6
8*2=16
8÷2=4
8+2=10
whichever operation it is