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3 years ago

Please help me I’ll will be marking brainliest please

Mathematics

2 answers:

My name is Ann [436]3 years ago

5 0

Answer:

$34.50

Step-by-step explanation:

First find out how much 1/4 of a lb will cost.

3.45/3= 1.15

This is the cost for only 1/4 a lbs of chopped walnuts. Take this number and multiply it by 4 to find how much it would cost for 1 whole pound of walnuts.

1.15x4= 4.60

It costs $4.60 for a whole pound of walnuts. If you are trying to find how much it costs for 7.5 lbs, then multiply 4.60 by 7.5.

4.60x7.5= 34.5

For 7.5 lbs of walnuts will cost $34.50

lesya [120]3 years ago

3 0

Answer:

it would cost $34.50 to purchase 7.5 lbs of walnuts.

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Parabola Equations - Algebra

mash [69]

Answer:

$h=-\frac{1}{6}x^2+2x$

Step-by-step explanation:

The height of the tunnel is modeled by:

$h=rx^2+tx$

Where r and t are constants.

We know that the maximum height of the tunnel h is 6 meters.

And at ground level, the width is 12 meters.

And we want to determine the equation of the parabola.

First, since this is a quadratic, our maximum height h will occur at the vertex of our equation.

The vertex is given by:

$(-\frac{b}{2a}, f(-\frac{b}{2a}))$

In our case, we have the function:

$h=(r)x^2+(t)x$

Hence, a=r; b=t; and c=0.

Therefore, our vertex is:

$\Rightarrow -\frac{t}{2r}$

Thus, if we substitute this back into our equation, we should get 6 since 6 is the maximum height which is determine by the vertex. In other words:

$(6)=r(-\frac{t}{2r})^2+t(-\frac{t}{2r})$

Simplify:

$6=r(\frac{t^2}{4r^2})-\frac{t^2}{2r}$

Simplify:

$6=\frac{t^2}{4r}-\frac{t^2}{2r}$

Combine fractions:

$6=\frac{t^2}{4r}-\frac{2t^2}{4r}=\frac{-t^2}{4r}$

Multiply both sides by the denominator:

$24r=-t^2$

Let's solve for the constant r. Divide both sides by 24. Hence:

$r=-\frac{t^2}{24}$

Now, we can use our knowledge of the width.

We know that the width is 12 meters at ground level.

Hence, when h=0, the difference of our roots is 12.

So:

$0=rx^2+tx$

We can factor:

$0=x(rx+t)$

By the Zero Product Property:

$x=0\text{ or } rx+t=0$

So, the first zero is 0.

Therefore, the second zero must be 12 to ensure that our width is 12.

Let's isolate the second zero. Subtract t from both sides:

$rx=-t$

Divide both sides by r:

$x=-\frac{t}{r}$

We know that this zero must be 12. Thus:

$12=-\frac{t}{r}$

We have previously solved for r. Substitute:

$12=-\frac{t}{\frac{-t^2}{24}}$

Simplify:

$12=\frac{24}{t}$

Take the reciprocal of both sides:

$\frac{t}{24}=\frac{1}{12}$

Multiply both sides by 24. Hence, the value of t is:

$t=2$

Now, we can find r. r is given by:

$r=-\frac{t^2}{24}$

By substituting 2 for t, then, we acquire that:

$r=-\frac{(2)^2}{24}=-\frac{4}{24}=-\frac{1}{6}$

Therefore, for:

$h=rx^2+tx$

Our equation is:

$h=-\frac{1}{6}x^2+2x$

7 0

3 years ago

State how many imaginary and real zeros the function has. f(x) = x4 - 8x3 + 17x2 - 8x +16

Lunna [17]

x^4 - 8x^3 + 17x^2 - 8x + 16 = 0
x^4 - 8x^3 + 16x^2 + x^2 - 8x + 16 = 0
x^2(x^2 - 8x + 16) + (x^2 - 8x + 16) = 0
(x^2 + 1)(x^2 - 8x + 16) = 0
(x^2 + 1)(x - 4)^2 = 0
x^2 + 1 = 0 or x - 4 = 0
x^2 = -1 or x = 4
x = +/- i or x = 4
Technically there are 2 imaginary solutions and 1 real solution. However, since the real solution occurs twice (multiplicity 2), you could say there are 2 real solutions (although they're the same). So the second answer would apply.

4 0

3 years ago

In the equation 24 divided by 1/2= ? Priya thinks the “?” Represents a number less than 24. Do you agree or disagree

almond37 [142]

Disagree because 24 divided by 1/2=48

Working out

24 divided by 1/2

To divide by a fraction, multiply by the reciprocal of that fraction

24 x 2

Multiply

48

Solution

48

5 0

4 years ago

How would changes in sample size affect the margin of error, assuming all else remained constant?

zaharov [31]

A larger sample size would cause the interval to narrow.

4 0

3 years ago

U4H1. Please help with this homework assignment- question is in the picture below:

Sphinxa [80]

It should be the 2nd one. I can't help with the drawing part though.

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3 years ago