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Evgesh-ka [11]
3 years ago
8

Write the equation 3x+2=4x²​ in standard form.

Mathematics
1 answer:
nignag [31]3 years ago
8 0

Answer:

Write the Equation in Standard Form 3x+2=4x^2. 3x+2=4x2 3 x + 2 = 4 x 2. To write an equation in standard form, move each term to the left side of the equation ...

Missing: 4x²​ ‎| Must include: 4x²​

Step-by-step explanation:

Write the Equation in Standard Form 3x+2=4x^2. 3x+2=4x2 3 x + 2 = 4 x 2. To write an equation in standard form, move each term to the left side of the equation ...

Missing: 4x²​ ‎| Must include: 4x²​

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Explain why triangleABC is similar to triangle triangle ADE
DedPeter [7]

Answer:

In the given figure, line segment is constructed on the triangle parallel to line segment . ... This line can then be considered as a transversal of these parallel lines. Angle and angle are therefore corresponding angles. And as they're corresponding, this means that they're equal.

7 0
2 years ago
Identify the ordered pair that represents the vector from a(-9,9) to b(7,3) and the magnitude of ab.
sveta [45]

Answer:

Answers below

Step-by-step explanation:

1. Order pair method

[(x2-x1) , (y2-y1)] = b-a = [(7--9) , (3-9)] = (16,-6)

2. Magnitude

|v| = \sqrt{16^2+-6^2}

v = |17.088|

7 0
3 years ago
Read 2 more answers
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
To solve X/0.4 = 10, you would: Add 0.4 Subtract 0.4 Multiply 0.4 Divide by 0.4
Mrac [35]
Multiply by 0.4 on both sides to cancel the original 0.4 and change the 10
8 0
3 years ago
The campers in cabin A walked 1/4 of the way to otter ridge (13 miles) How many miles did they walk?
shusha [124]
The question demands that we find a fraction of a given quantity.

The 'of ' means multiplication.

So the total distance of the journey was

13 \: miles

But they walked ¼ of the whole journey. We are supposed to find

\frac{1}{4} \: of \: 13 \: miles
\\= \frac{1}{4} \times 13 \: miles

= \frac{13}{4} \: miles

= 3.25\: miles

Hence they walked 3.25 miles.
3 0
3 years ago
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