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3 years ago

Two less than six times the difference of a number and five

Mathematics

2 answers:

Luda [366]3 years ago

6 0

2-(6x x-5) would be the answer

KiRa [710]3 years ago

5 0

The difference of a number and 5 is: x - 5

6 times of that is:

6 * (x - 5)

2 less than THAT is:

6 * (x - 5) - 2

The answer is 6 * (x - 5) - 2.

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F(x) ≥ -(x+4)^2 axis of symmetry: vertex:

BlackZzzverrR [31]

Answer:

so the vertex is (-4, 0) and the axis of symmetry is x=-4

Step-by-step explanation:

f(x) ≥ -(x+4)^2

f(x) ≥ -(x- -4)^2

this is in the form

f(x)> a(x-h)^2 +k

where (h,k) is the vertex and h is the axis of symmetry

so the vertex is (-4, 0) and the axis of symmetry is x=-4

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Answer:

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Step-by-step explanation:

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3 years ago

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What is the equation of the line that passes through the point (4.11) and is perpendicular to the line with the following equati

Klio2033 [76]

Answer:

$y = x +7$

Step-by-step explanation:

Given

$Point\ (x_1,y_1) = (4,11)$

Perpendicular to $y = -x + 14$

Required

Determine the line equation

An equation has the form

$y = mx + b$

Where

$m = slope$

By comparison with $y = -x + 14$

$m = -1$

Because the line is perpendicular to $y = -x + 14$ , the following relationship exists

$m_1 = \frac{-1}{m}$ i.e. the condition for perpendicularity

Where m1 is the slope of the equation that passes through $Point\ (x_1,y_1) = (4,11)$

So, we have:

$m_1 = \frac{-1}{-1}$

$m_1 = 1$

The line equation is then calculated using:

$y - y_1 = m_1(x - x_1)$

Where

$m_1 = 1$

$Point\ (x_1,y_1) = (4,11)$

So, we have:

$y - 11 = 1(x - 4)$

$y - 11 = x - 4$

Add 11 to both sides

$y - 11+11 = x - 4+11$

$y = x - 4+11$

$y = x +7$

The B, C and D parts of your question are not clear.

Apply the same steps used in (a) above and you'll get your answers

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3 years ago