The mean absolute deviation for the number of hours students practiced the violin is 6.4.
<h3>What is the mean absolute deviation?</h3>
The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.
Given
Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.
The given data set is;
45, 38, 52, 58, 42
Mean Deviation = Σ|x − μ|/N.
μ = mean, and N = total number of values
|x − μ| = |45 − 47| = 2
|38− 47| = 9
|52− 47| = 5
|58− 47| = 11
|42− 47| = 5
The mean absolute deviation for the number of hours students practiced the violin is;
Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.
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Answer:
the answer is 445.5
Step-by-step explanation:
what I did was divide 50 by 495 and got 9.9 then since it took 45 minutes every 50 square feet of floor i multiplied 45 x 9.9 and got 445.5
Answer:
Final answer is 
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y
Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:
Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is
Answer:
i'm pretty sure it is C..
Step-by-step explanation:
Answer:
Semi-monthly gross pay = $662.5
Step-by-step explanation:
Given:
Earning per hour = $13.25
Number of hours per week = 25 hours
Find:
Semi-monthly gross pay
Computation:
Assume two week in semi-month
So,
Total working hour = 2(25)
Total working hour = 50 hours
Semi-monthly gross pay = Total working hour × Earning per hour
Semi-monthly gross pay = 50 × 13.25
Semi-monthly gross pay = $662.5
