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Ilia_Sergeevich [38]
3 years ago
9

Giving out 16 points if you can help me :))

Mathematics
1 answer:
Paraphin [41]3 years ago
3 0

Answer:

g(x)=-6x+5

Step-by-step explanation:

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Answer:

I dont understand that sorry

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What is 8777 divided by 456​
zimovet [89]
Your answer is 19.25.
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An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth
dedylja [7]

Answer:

(a) D(t) = 250t -500 miles

(b) Controller has 2 hours, but including time for pilots to divert course or altitude.

Step-by-step explanation:

Given:

two planes at same altitude heading in a collision course.

Plane A at 400 miles from collision point at 200 mph

Plane B at 300 miles from collision point at 150 mph.

Theoretical collision happens in

t = 400/200 = 300/150 = 2 hours

Distance ya of plane A from collision point as a function of time in hours

ya(t) = 400 -200t

Distance yb of plane B from collision point as a function of time in hours

yb(t) = 300-150t

(a) Distance between two planes,

Since the two planes are on courses perpendicular to each other, will need using pythagorean theorem

D(t) = sqrt(ya(t)^2+yb(t)^2)

= sqrt((400-200t)^2+(300-150t)^2)

= 250(t-2)

D(t) = 250t -500 miles

b. time available

Time until D(t) = 0

solve D(t) = 0

D(t) = 0

250(t-2) = 0

t = 2  (two hours)

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3 years ago
How would I solve this step by step? ​
hoa [83]

Answer:

Step-by-step explanation:

you would add 60 + 90 then subtract it from 180

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Question in pic. Plz open the pic for the question ..corect gets branliest
mel-nik [20]
<h2><u>Answer with explanation</u>:</h2>

Given: In Δ ABC and ΔAEC,

AB=BC and AD=CD

i) In ΔADB and CBD, we have

AD = DC        [given]

AB=BC           [given]

DB= DB           [given]

⇒ ΔADB ≅ΔCDB   [By SSS congruence rule]

⇒ ∠ADB ≅∠CDB       ...(i)           [Corresponding parts of congruent triangles are congruent]

Since AC is a straight line,

∠ADB+∠CDB = 180°   [Linear pair]

⇒∠ADB+∠ADB=180°   [from (i)]

⇒2 ∠ADB=180°  

⇒∠ADB=90°  =∠CDB

Also ∠ADB+∠ADE=180°   [Linear pair]

⇒∠ADE=180°-∠ADB  = 180°-90°

⇒∠ADE=90°, i.e. ∠ADE is a right triangle.

Similarly, ∠CDB+∠CDE=180°

⇒∠CDE=90°

ii) Now, in ΔADE and CDE

AD= CD   [given]

ED=ED   [Common]

∠ADE= ∠CDE = 90°

⇒ΔADE ≅ CDE   [By SAS congruence rule ]

⇒AE=EC   [Corresponding parts of congruent triangles are congruent]

Hence proved.

6 0
3 years ago
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