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2 years ago

Simplify 1/a+b + 1/a-b + 2b/a^2-b^2

Mathematics

1 answer:

Simora [160]2 years ago

8 0

Answer:

−a^2 b^2 + 2a + 2b

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a^2

Step-by-step explanation:

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What is 35-14+27 i really need help pls anser fast

zhuklara [117]

Answer:

B is the correct answer, The first choice (which you chose) is the incorrect answer.

Step-by-step explanation:

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2 years ago

[HELP ASAP]~ A city has a population of 240000 people. Suppose that each year the population grows by 4%. What will the populati

Georgia [21]

Answer:

multiply the population each year by 4% or 0.04

year 1 increase by 9600, population 249,600

year 2 increase by 9984, population 259,584

year 3 increase by 10,383, 269,967

year 4 increase by 10,799, 280,766

year 5 increase by 11,231, 291,997

year 6 increase by 11,680, 303, 677

Step-by-step explanation:

I rounded the totals.

8 0

3 years ago

4x-5=2x+7 midpoint segmen

Bogdan [553]

Answer:

x = 6

Step-by-step explanation:

The way to solve this is by subtracting 2x from both sides. Now we have

2x-5=7

Then we add 5 from both sides. Now we have

2x=12

We do this because we want X by itself

Then we divide by 2 on both sides and now we have

x = 6

If you have any questions feel free to ask in the comments.

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3 years ago

Which two equations would be represented as parallel lines?

Mariana [72]

Answer:

The first and third options are parallel.

Step-by-step explanation:

They both have a slope of 2.

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4 0

3 years ago

Read 2 more answers

In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. In the same year

LenaWriter [7]

Answer:

Step-by-step explanation:

Let x represent the number of years it will take the two colleges to have the same enrollment.

In 2000, there were 12900 students at college A, with a projected enrollment increase of 900 students per year. This means that the expected number of students at college A in x years time is

12900 + 900x

In the same year, there were 25,000 students at college B, with a projected enrollment decline of 700 students per year. This means that the expected number of students at college B in x years time is

25000 - 700x

For both colleges to have the same enrollment,

12900 + 900x = 25000 - 700x

900x + 700x = 25000 - 12900

1600x = 12100

x = 12100/1600

x = 7.56

Approximately 8 years

The year would be 2000 + 8 = 2008

4 0

3 years ago

Simplify 1/a+b + 1/a-b + 2b/a^2-b^2​

Simplify 1/a+b + 1/a-b + 2b/a^2-b^2