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geniusboy [140]
2 years ago
12

Find a digit to make numbers that are divisible by 12 if it is possible: 9__32

Mathematics
2 answers:
Sergeu [11.5K]2 years ago
6 0

Answer:

the anser is 9132

Step-by-step explanation: because i put 0 and its not divisible then i put 1 and it was divisibe.

alukav5142 [94]2 years ago
4 0

Answer:

Step-by-step explanation:

Any digit will work if remainders are allowed.

If you want only whole number results

9132/12 = 761

9432/12 = 786

9732/12 = 881

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The sun of three consecutive integers is 60 find the integers
prohojiy [21]

Answer:

<em>let </em><em>the </em><em>three</em><em> </em><em>consecutive</em><em> Integers</em><em> </em><em>be</em>

<em>x </em><em>,</em><em> </em><em>x+</em><em>1</em><em> </em><em>,</em><em> </em><em>x+</em><em>2</em>

<em>their </em><em>sum </em><em>is </em><em>6</em><em>0</em><em>,</em>

<em>so,</em>

<em>x </em><em>+</em><em> </em><em>x </em><em>+</em><em> </em><em>1</em><em> </em><em>+</em><em> </em><em>x </em><em>+</em><em> </em><em>2</em><em> </em><em>=</em><em> </em><em>6</em><em>0</em>

<em>→</em><em> </em><em>3</em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>6</em><em>0</em>

<em>→</em><em> </em><em>3</em><em>x</em><em> </em><em>=</em><em> </em><em>6</em><em>0</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>5</em><em>7</em>

<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>7</em><em>/</em><em>3</em><em> </em><em>=</em><em> </em><em>1</em><em>9</em>

<em>therefore</em><em>,</em><em> </em><em>1</em><em>s</em><em>t</em><em> </em><em>integer </em><em>=</em><em> </em><em>1</em><em>9</em>

<em>2</em><em>n</em><em>d</em><em> </em><em>integer </em><em>=</em><em> </em><em>x </em><em>+</em><em> </em><em>1</em><em> </em><em>=</em><em> </em><em>1</em><em>9</em><em> </em><em>+</em><em> </em><em>1</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em>

<em>3</em><em>r</em><em>d</em><em> </em><em>integer </em><em>=</em><em> </em><em>x </em><em>+</em><em> </em><em>2</em><em> </em><em>=</em><em> </em><em>1</em><em>9</em><em> </em><em>+</em><em> </em><em>2</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em>

<em>so,</em>

<em>the </em><em>three </em><em>consecutive</em><em> Integers</em><em> </em><em>are </em><em>1</em><em>9</em><em> </em><em>,</em><em> </em><em>2</em><em>0</em><em> </em><em>and </em><em>2</em><em>1</em><em>.</em>

<em><u>hope</u></em><em><u> this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> dear</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u> take</u></em><em><u> care</u></em><em><u> and</u></em><em><u> may</u></em><em><u> u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> </u></em><em><u>day </u></em><em><u>ahead</u></em><em><u>!</u></em>

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The first x coordinate is given by 0 and the second one is given as j. So the length of the base is j. (Sometimes in math they give letters rather than numbers. And since you know it is an isosceles then the other vertex should be at x-coordinate half j or j/2.
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