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3 years ago

HELP WITH MY WHOLE TEST ;-; jensnshsjsjjsjsjsjsjsksksmsknnknksnisi

Mathematics

2 answers:

AfilCa [17]3 years ago

8 0

The answer should be -6.

yaroslaw [1]3 years ago

4 0

Answer:

-6

simplify (3-1) first. 3-1 is 2 and then multiply -4 by 2 which is -8. -8 plus 2 is -6. :)

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Answer:

Part (A) The required PMF is: $P(X=x)=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}$

Part (B) $B(x;n,p)=\binom{10}{x}(0.3)^x(1-0.3)^{10-x}$

Step-by-step explanation:

Consider the provided information.

There are 50 industrial rms. An inspector will visit 10 randomly selected rms to check for violations of regulations.

Part (A)

15 of the rms are actually violating at least one regulation.

Let X is the number of firms violate at least one regulation from 10 randomly selected rms to check for violations of regulations out of 50 firms of which 15 5 of the rms are actually violating.

Therefore, $X\sim Hypergeom(n=10, M=15\ and\ N=50)$

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$P(X=x)=Hyper(x; n=10, M=15, N=50)\\=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}$

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Here N=500 so find the probability of p as shown below:

$p=\frac{150}{500} =0.3$ and n=10

$B(x;n,p)=B(x;10,0.3)\\=\binom{10}{x}(0.3)^x(1-0.3)^{10-x}$

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