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Phantasy [73]
3 years ago
6

Is 4cm by 11cm by 3cm a triangle

Mathematics
1 answer:
Kaylis [27]3 years ago
5 0
Yes it is a triangle
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Which is not a factor of 48? A. 8 B. 14 C. 16 D. 24
alexira [117]
14 is not a factor of 48
7 0
3 years ago
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125
Marina CMI [18]

Answer:

2m

Step-by-step explanation:

2250 \div 25 = 90

90 \div 45 = 2

7 0
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At midnight, the temperature was -8° F. At noon, the temperature was 23° F. Which expression represents the increase in temperat
Mariana [72]

Answer:

C

Step-by-step explanation:

Increase is difference between ending and begining value so 23-(-8) =23+8.

In this case its absolute value because it has to be positive

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4 years ago
Help me i need it right now pls
Soloha48 [4]

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6 0
3 years ago
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assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
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